1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Flauer [41]
3 years ago
8

A cell phone tower is 120 ft tall. The pole creates a 74 ft shadow. What is the angle of elevation of the sun? Round your answer

to the nearest degree

Mathematics
1 answer:
Zigmanuir [339]3 years ago
4 0

The angle of elevation is 58 degrees

<em><u>Solution</u></em>:

Given that cell phone tower is 120 feet tall

The tower creates a 74 feet shadow

To find: angle of elevation of sun

The cell phone tower and base ( shadow) forms a right angled triangle

The figure is attached below

ABC is right angled triangle

AC = height of tower = 120 feet

AB = length of shadow = 74 feet

We have to find the angle of elevation

By definition of tan,

tan \theta = \frac{height}{base}\\\\tan \theta = \frac{AC}{AB}\\\\tan \theta = \frac{120}{74}\\\\tan \theta = 1.621\\\\\theta = tan^{-1}{1.621}\\\\\theta = 58.32 \approx 58

Thus angle of elevation is 58 degrees

You might be interested in
Order the set of numbers from least to greatest:<br> -5, - 26,-31
34kurt

Answer:

-31, -26, -5

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
What is 3(exponent 2) multiplied by 3(exponent 3) ????
rusak2 [61]

                                                   \huge\boxed{243}

___________________________________________________________

                                             \boxed{Explanation}

So, we have the following equation...

3^2*3^3=(?)

Remember 3^2 and 3^3 is the following...

3^2=3*3\\3^3=3*3*3

Therefore, 3*3=9\\3*3*3=27\\9*27=243

So, your final answer is \boxed{243}.

___________________________________________________________

<em>Glad to help!</em>

\huge\boxed{Thanks,\;Plip.}

3 0
3 years ago
Read 2 more answers
Identify the domain and range of each relation. Use a mapping diagram to determine whether the relation a function.
Xelga [282]

Answer:

Domains- 6, 5, 1, 7

Ranges- -7, -8, 4, 5

6 0
3 years ago
To solve the system of equations by elimination, what could you multiply each equation by to cancel out the x-variable?A:6x-3y=-
Novay_Z [31]

Answer:

Step-by-step explanation:

You could multiply all of equation A by 1/6 and all of equation b by -1/4 to get

A. x-3/2y=-1/3 and B. x+1/4y=/5/4, then subtract the equations from each other to solve

8 0
3 years ago
you have a 20 ounce bottle of juice. you pour out 1/4 of the bottle to share with a friend. if your our out 3 ounces for yoursel
seropon [69]
12 ounces will be left in the bottle

Turn the 1/4 into a decimal which is 0.25 and times that by 20 and you’ll get 5, 5 is the amount of ounces you poured for your friend. Subtract 20 ounces by 5 ounces and you’ll get 15 ounces, then subtract 15 by 3 which is the amount of juice you poured for yourself and you’ll be left with 12 ounces in the bottle.
5 0
3 years ago
Other questions:
  • What is the area of the trapezoid?<br><br><br> 176 cm2<br> 192 cm2<br> 208 cm2<br> 224 cm2
    10·2 answers
  • Is .07 greater than .007?
    7·1 answer
  • Please help! (Picture shown)
    5·1 answer
  • Helppppppppppppppppppppp
    12·1 answer
  • Help,, i'll mark as brainliest
    15·1 answer
  • A car travels a distance of 360 miles in 6 hours. What is the average speed of the car for this trip? Solve for speed.
    6·1 answer
  • Can someone help me with finding the slope of the graph- ONLY GRAPH
    7·1 answer
  • To get into shape, Miles ran for 1 minute on Monday, 3 minutes on Tuesday, 6 minutes on Wednesday, and 10 minutes on Thursday. I
    7·2 answers
  • can anyone help me to get the answers please its important 5. An item marked at ₹ 340 is sold for ₹ 324. What is the discount? 6
    13·1 answer
  • What is the percent of increase from 40.6 to 81.2?
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!