1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Talja [164]
3 years ago
12

Directions : find the area of each figure . round to the nearest tenth if necessary.

Mathematics
2 answers:
12345 [234]3 years ago
8 0
First split the box
I am going to spilt the bottom part so the bottom box is 18 and 6
And the top is 12 and 6 because the 12 had to be cut in half final multiply 18 times six and then add 12 times 6.
So the answer is 180 cm^2
alexdok [17]3 years ago
4 0
12x18 + 6x6 = 252cm²
You might be interested in
A rectangle has length 72 cm and it’s width 56 cm. The other rectangle has the same area as this one, but its width is 21 cm. Fi
Kryger [21]

A = l*w

A = 72* 56

A= 4032


4032 = L*21

4032/21 =L

L =192


5 0
3 years ago
Forgot to do this over winter break. Its due tomorrow and I haven't used my brain for 2 weeks. HELPPP (may have to zoom in)
ANEK [815]
1. 60,30,90 right triangle. y will be hypotenuse/2, x will be
hypotenuse*sqrt(3)/2. So x = 16*sqrt(3)/2 = 8*sqrt(3), approximately 13.85640646 
y = 16/2 = 8  
2. 45,45,90 right triangle (2 legs are equal length and you have a right angle).
X and Y will be the same length and that will be hypotenuse * sqrt(2)/2. So 
x = y = 8*sqrt(2) * sqrt(2)/2 = 8*2/2 = 8 
 3. Just a right triangle with both legs of known length. Use the Pythagorean theorem 
x = sqrt(12^2 + 5^2) = sqrt(144 + 25) = sqrt(169) = 13  
4. Another right triangle with 1 leg and the hypotenuse known. Pythagorean theorem again. 
y = sqrt(1000^2 - 600^2) = sqrt(1000000 - 360000) = sqrt(640000) = 800  5. A 45,45,90 right triangle. One leg known. The other leg will have the same length as the known leg and the hypotenuse can be discovered with the Pythagorean theorem.  x = 6. y = sqrt(6^2 + 6^2) = sqrt(36+36) = sqrt(72) = sqrt(2 * 36) = 6*sqrt(2), approximately 8.485281374  
6. Another 45,45,90 triangle with the hypotenuse known. Both unknown legs will have the same length. And Pythagorean theorem will be helpful. 
x = y. 
12^2 = x^2 + y^2 
12^2 = x^2 + x^2 
12^2 = 2x^2 
144 = 2x^2 
72 = x^2 
sqrt(72) = x 
6*sqrt(2) = x 
x is approximately 8.485281374  
7. A 30,60,90 right triangle with the short leg known. The hypotenuse will be twice the length of the short leg and the remaining leg can be determined using the Pythagorean theorem. 
y = 11*2 = 22. 
x = sqrt(22^2 - 11^2) = sqrt(484 - 121) = sqrt(363) = sqrt(121 * 3) = 11*sqrt(3). Approximately 19.05255888  
8. A 30,60,90 right triangle with long leg known. Can either have fact that in that triangle, the legs have the ratio of 1:sqrt(3):2, or you can use the Pythagorean theorem. In this case, I'll use the 1:2 ratio between the unknown leg and the hypotenuse along with the Pythagorean theorem. 
x = 2y 
y^2 = x^2 - (22.5*sqrt(3))^2 
y^2 = (2y)^2 - (22.5*sqrt(3))^2 
y^2 = 4y^2 - 1518.75 
-3y^2 = - 1518.75 
y^2 = 506.25 = 2025/4 
y = sqrt(2025/4) = sqrt(2025)/sqrt(4) = 45/2 
Therefore: 
y = 22.5
 x = 2*y = 2*22.5 = 45  
9. Just a generic right triangle with 2 known legs. Use the Pythagorean theorem. 
x = sqrt(16^2 + 30^2) = sqrt(256 + 900) = sqrt(1156) = 34  
10. Another right triangle, another use of the Pythagorean theorem. 
x = sqrt(50^2 - 14^2) = sqrt(2500 - 196) = sqrt(2304) = 48
8 0
3 years ago
Please Find the value of x and y
Free_Kalibri [48]

Answer: x=40° and y=140°

Step-by-step explanation:

From the figure, we know that x and 40 are vertical angles. Therefore, they are equal to each other.

x=40°

With the value of x, we know that x and y are supplementary angles. That means they are equal to 180°.

40+y=180       [subtract both sides by 40]

y=140°

Now we know x=40° and y=140°.

4 0
2 years ago
Suppose you have some wolves and some dogs. Dogs are named and wolves are not. If you call a dog it will run to you. A wolf woul
Ira Lisetskai [31]

Answer:

4dogs and no wolves

Step-by-step explanation:

when a dog is taken care of (Trained) it could be let to run free in a definite region.

On a plane with one line we can place two dogs (one dog in each of the regions) and they will not fight as they will be separated by a line, and they will run free.

If we place three lines in general, then we would have four regions where 4 dogs can run free as they are separated by a line so as not to fight.

But for Wolves from the question it is deduced that:  A wolf has to be caged all the time and no matter how well you train a wolve, it wont yield to instructions.

With these two, wolves wont be allowed on the plane at all.

8 0
3 years ago
There are 6 quarters in a jar. Jill adds 2 quarters to the jar every day. Which linear equation represents the total amount of q
I am Lyosha [343]
<span>Given: Say 6Q = 6 quarters in a jar 2Q is added everyday After X days, Amount of quarters = 6Q + (2Q * X) So answer would be: D) which is y = 2x + 6</span>
8 0
3 years ago
Read 2 more answers
Other questions:
  • the sum of an integer and seven more than four times the next consecutive integer is 66. find the integers
    7·1 answer
  • If 2a+ 2/a =4, what is the value of 2a^2− 2/a^2 ?
    11·1 answer
  • What is this Method???
    12·2 answers
  • Learning Task 1: Write and answer the following in your answer sheet
    6·1 answer
  • Explanation would be appreciated, last word is indicated.​
    12·1 answer
  • Steps factoring polynomials using gcf for 9x²+9x
    12·1 answer
  • This week Kent works 15 hours at$12.50 an hour His Paycheck Including his commission was $263.85 can was to know how much earned
    6·2 answers
  • Please help me grades all most here
    7·1 answer
  • The fish population in a certain part of the ocean(in thousnad of fish) as a dunction of the waters temperature(in degrees Celci
    6·1 answer
  • Can someone please help me fill in the answer in the bottom.​
    15·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!