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alex41 [277]
3 years ago
15

To rent a van, a moving company charges $50.00 plus $5.50 per mile. The table shows the total cost for the number of miles drive

n. Enter an equation in slope-intercept form to represent this situation.

Mathematics
1 answer:
LuckyWell [14K]3 years ago
5 0
Y = 55/10x + 50 is the equation to represent this situation
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Graph a line that contains the point -6,1 and has a slope of 5
Stells [14]

Answer:

y=5x+31

Step-by-step explanation:

y=mx+b

1=(-6*5)+b

1=-30+b

31=b

y=5x+31

(5*-6)+31

-30+31

1

you can also graph a line on desmos

7 0
3 years ago
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What are factors of 27?
Artyom0805 [142]
The answer would be 3^33
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3 years ago
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I arrive at a bus stop at a time that is normally distributed with mean 08:00 and SD 2 minutes. My bus arrives at the stop at an
Nimfa-mama [501]

Answer:

0.0485 = 4.85% probability that you miss the bus.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

When two normal distributions are subtracted, the mean is the subtraction of the means, while the standard deviation is the square root of the sum of the variances.

In this question:

We have to find the distribution for the difference in times between when you arrive and when the bus arrives.

You arrive at 8, so we consider the mean 0. The bus arrives at 8:05, 5 minutes later, so we consider mean 5. This means that the mean is:

\mu = 0 - 5 = -5

The standard deviation of your arrival time is of 2 minutes, while for the bus it is 3. So

\sigma = \sqrt{2^2 + 3^2} = \sqrt{13}

The bus remains at the stop for 1 minute and then leaves. What is the chance that I miss the bus?

You will miss the bus if the difference is larger than 1. So this probability is 1 subtracted by the pvalue of Z when X = 1.

Z = \frac{X - \mu}{\sigma}

Z = \frac{1 - (-5)}{\sqrt{13}}

Z = \frac{6}{\sqrt{13}}

Z = 1.66

Z = 1.66 has a pvalue of 0.9515

1 - 0.9515 = 0.0485

0.0485 = 4.85% probability that you miss the bus.

5 0
3 years ago
Please help me with this questions
viktelen [127]

Answer:

See attached

Step-by-step explanation:

The answers added on the picture

8 0
3 years ago
Solve please. Fastest + most accurate answer gets brainliest.
asambeis [7]

Answer:

QPR is 47

Step-by-step explanation:

I dont know the rest sorry

4 0
2 years ago
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