Answer:
1.-t₁ = 0,625 s
2.-h(max) = 6,25 f
3.-t = 1,25 s
Step-by-step explanation:
V₀ = 20 f/s
h(t) = - 16*t² + 20*t
h(max) = ??
h´(t) = - 32*t + 20
h(max) will occurs when V = 0 dh/dt = 0 then
- 32*t + 20 = 0
- 32*t = -20
t = 20/32
t₁ = 0,625 s
h(max) = h(0,625) = - 16*(0,625)² + 20*0,625
h(max) = - 6,25 + 12,5
h(max) = 6,25 f
c) The ball will hit the ground
t = 2*t₁
t = 2*0,625
t = 1,25 s
First, determine the number of computers that are needed for 924 students.
n = (924 students)(5 computers / 12 students)
n = 385 computers
Since, there are only 125 computers, the difference can be calculated.
d = 385 computers - 125 computers
d = 260 computers
Hence, 260 more computers are still needed.
Answer:
50.266 or 50.27
Step-by-step explanation:
X^2 - x - 6 > 0
(x - 3)(x + 2) > 0
x < - 2 or x > 3
answer
x < - 2 or x > 3
