"As part of integrating your solution your client indicates that they have certain technologies enabled on their network that al
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Answer:
Explanation:
The following code is written in Java and uses a for loop with a series of IF ELSE statements to check the next and previous characters in a string. Checking to make sure that there are no asterix. If so it adds that character to the String variable output. Which is returned to the user at the end of the method. Two test cases have been created and the output can be seen in the attached image below.
class Brainly {
public static void main(String[] args) {
System.out.println(starOut("sm*eilly"));
System.out.println(starOut("ab**cd"));
}
public static String starOut(String str) {
String output = "";
for (int i = 0; i < str.length(); i++) {
if ((i != 0) && (i != str.length()-1)) {
if ((str.charAt(i-1) != '*') && (str.charAt(i+1) != '*') && (str.charAt(i) != '*')) {
output += str.charAt(i);
}
} else {
if ((i == 0) && (str.charAt(i) != '*') && (str.charAt(i+1) != '*')) {
output += str.charAt(i);
} else if ((i == str.length()-1) && (str.charAt(i) != '*') && (str.charAt(i-1) != '*')) {
output += str.charAt(i);
}
}
}
return output;
}
}
