Question

HELP!!! Will give brainliest!!! How do you slove a two step equation with fractions involved?

Answer 1

I hope that this is what you are looking for

Step-by-step explanation:

Let's take the following question as an example,

$\frac{2}{3} x-\frac{1}{4} = \frac{1}{6}$

Start by adding 1/4 to both sides.

$\frac{2}{3} x - \frac{1}{4} + \frac{1}{4} = \frac{1}{6} + \frac{1}{4}$

$\frac{2}{3}x = \frac{1}{6}+ \frac{1}{4}$

To add both 1/6 and 1/4 together we must have a common denomitor.

The common denominator for 1/6 and 1/4 is 12

$\frac{2}{3}x = (\frac{1}{6}*\frac{2}{2} ) + (\frac{1}{4}*\frac{3}{3} )$

Multiple to get the common denomiators

$\frac{2}{3}x = (\frac{2}{12}) + (\frac{3}{12} )$

Now we can add the fractions.

$\frac{2}{3}x = \frac{5}{12}$

To get the x by itself we can either multiple by the reciprobcal of 2/3 or multiple by 3 and then divide by 2

$(\frac{3}{2} )* \frac{2}{3} x = (\frac{5}{12})(\frac{3}{2})$

The left side will become x as 3/2 and 2/3 cancel each other out

$x = (\frac{5}{12}) (\frac{3}{2})$

Multiple the right side to get a value for x

$x = \frac{15}{24}$ or $x = \frac{5}{8}$

If you notice we can simplfy the fraction to 5/8