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eimsori [14]
3 years ago
7

12 + 6 − 4 ÷ (2 + 5)

Mathematics
1 answer:
astra-53 [7]3 years ago
7 0

Answer:

2

Step-by-step explanation:

14 / (7)

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The height of a certain banner is equal to one third of its length. If the banner is 5 ft tall, write the equation that can be u
pav-90 [236]

Answer:

L=3h

Step-by-step explanation:

Let height of a banner be h, then we know that this is \frac{1}{3} of the length L of the banner; so we have

h=\frac{1}{3} L .

Now we can rearrange this equation to solve for the length of the banner given it's height:

L=3h

So there we have it!

If the banner is 5 ft tall, then it's length will be:

L=3*5=15ft

5 0
3 years ago
Solve the quadratic equation by completing the square.
Step2247 [10]

Answer:

x1, x2 = 4.74 , -2.74

Step-by-step explanation:

To find the roots of a quadratic function we have to use the bhaskara formula

ax^2 + bx + c

x^2 - 2x - 13

a = 1     b = -2    c = -13

x1 = (-b + √ b^2 - 4ac)/2a

x2 =(-b - √ b^2 - 4ac)/2a

x1 = (2 + √ (2^2 - 4 * 1 * (-13)))/2 * 1

x1 = (2 + √ (4 + 52)) / 2

x1 = (2 + √ 56 ) / 2

x1 = (2 + 7.48) / 2

x1 = 9.48 / 2

x1 = 4.74

x2 = (2 - √ (2^2 - 4 * 1 * (-13)))/2 * 1

x2 = (2 - √ (4 + 52)) / 2

x2 = (2 - √ 56 ) / 2

x2 = (2 - 7.48) / 2

x2 = -5.48 / 2

x2 = -2.74

6 0
3 years ago
There are a total of 127 cars and trucks in a lot. If there are four more than twice the number of tricks than cars, how many ca
Kruka [31]
There are a total of 127 cars on a lot if there are four more than twice the number of trucks than cars how any trucks and cars are on the lot
4 0
3 years ago
Factors of 64a3 - 343b 3 are
bearhunter [10]

\huge\mathfrak\green{Constant}

Constant is the number that cannot change the value

Im not sure..but you can copy it

8 0
3 years ago
Find the midpoint of the segment with the following endpoints.<br> (8,4) and (2,7)
Fudgin [204]

Answer:

Step-by-step explanation:

Use the midpoint formula: \frac{ChangeInX}{2} ,\frac{ChangeInY}{2}

So, the Change In X is 2-8 = -6

And the Change in Y is 7-4 = 3

Once you divide both of the changes by 2, you get

X: -3

Y:  \frac{3}{2}

So the midpoint is: (-3,\frac{3}{2})

4 0
3 years ago
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