Answer:
The ER diagram for the auto service is shown in the attachment.
Answer:
// here is code in c++.
#include <bits/stdc++.h>
using namespace std;
// main function
int main() {
// variable
int num;
int tot_sum=0;
cout<<"enter a number: ";
// read the value of n
cin>>num;
// check the multiple of 2 or 5 from 1 to n
for(int x=1;x<=num;x++)
{
// if multiple of 2 or 5 then add them
if(x%2==0 ||x%5==0)
{
tot_sum=tot_sum+x;
}
}
// print the sum
cout<<"sum of multiple of 2 or 5 is:"<<tot_sum<<endl;
return 0;
}
Explanation:
Read the number "n" from user.Check every number from 1 to n, if it is a multiple of 2 or 5 then add them to "tot_sum".When the for loop end, "tot_sum" will have sum of all the number which are either multiple of 2 or 5.Print the sum.
Output:
enter a number:11
sum of multiple of 2 or 5 is:35
charles babbage is the father of computer's
Answer:
for y in range(88, 43, -4):
print(y, end=" ")
Explanation:
yw
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