Answer:
6 offsprings with white fur
Explanation:
The gene involved here codes for fur colour in mice where the allele for brown fur (B) is dominant over the allele for white fur (b) i.e. the B allele will mask the expression of b allele in an heterozygous state (Bb).
Since allele B is dominant, in an heterozygous state (Bb), the mice will be brown-furred. Hence in a cross between two Bb parents, a phenotypic ratio of 1:2:1 will be produced where;
1 is BB (homozygous brown fur), 2 is Bb (heterozygotic brown fur) and 1 is bb (homozygous white fur).
Hence, 1/4 × 100= 25% offsprings will be white furred. If 24 mice result, 25/100 × 24 = 6 offsprings will be white.
1. is B Horst
2. is A Graben
Answer: 12
Explanation: the reaction is: C6H12O6 + 6 H2O + 6 O2 -> 6 CO2 + 12 H2O + 38 ATP + heat
Because of the 2 glucose molecules you multiply the stoichiometry with a factor 2 so: 2 x 6 O2 = 12 O2
Answer:
If a cell has not properly copied its chromosomes or there is damage to the DNA, the CDK will not activate the S phase cyclin and the cell will not progress to the G2 phase. The cell will remain in S phase until the chromosomes are properly copied, or the cell will undergo programmed cell death.
Explanation:
I hope it's help
Answer:
By spliting them up it would be most simular to how sex cells work with traits that produce 4 possible outcomes
Explanation:
