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Tomtit [17]
4 years ago
15

I need help,I need to use substitution but I don't know how

Mathematics
1 answer:
lions [1.4K]4 years ago
8 0

If y=x+6 and y=-2x-3, then you can replace y in either equation with the equivalent expression given by the other equation. In this case, you have

x+6=-2x-3

and you can solve for x.

x+2x+6-6=-2x+2x-3+6\implies3x=3\implies\dfrac{3x}3=\dfrac33\impliesx=1

Then y=1+6=7.

For the second system, you can write

5x-y=-5\implies 5x-5x-y=-5-5x\implies-y=-5-5x

\implies-(-y)=-(-5-5x)\implies y=5+5x

Then substitute this into the second equation and you get

3x-6(5+5x)=24\implies3x-30-30x=24\implies-27x-30+30=24+30

\implies-27x=54\implies x=2

so that

y=5+5(2)=15

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