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dem82 [27]
3 years ago
7

How do i expand (3x+5)^2

Mathematics
2 answers:
shepuryov [24]3 years ago
8 0
I don't know how you expand it but the answer is 3x + 25 unless that's expanding.
alisha [4.7K]3 years ago
3 0
(3x + 5)^2 expands into two binomials: (3x + 5)(3x +5)

from there, you foil them:
(3x + 5)(3x + 5)
multiply the first terms ... 9x^2
the inside terms ... 9x^2 + 15x
outside terms ... 9x^2 + 15x + 15x
last terms ... 9x^2 + 15x + 15x + 25
then add like terms ... 9x^2 + 30x + 25

that's the expanded binomial!!
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3 years ago
Evaluate the expression when x = 5<br> Am I correct? Is 5 the answer? I’m confused.
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How do I solve question 6 through 8?<br> Solve for me
rewona [7]

The equations of the functions are y = -4(x + 1)^2 + 2, y = 2(x - 2)^2 + 1 and y = -(x - 1)^2 - 2

<h3>How to determine the functions?</h3>

A quadratic function is represented as:

y = a(x - h)^2 + k

<u>Question #6</u>

The vertex of the graph is

(h, k) = (-1, 2)

So, we have:

y = a(x + 1)^2 + 2

The graph pass through the f(0) = -2

So, we have:

-2 = a(0 + 1)^2 + 2

Evaluate the like terms

a = -4

Substitute a = -4 in y = a(x + 1)^2 + 2

y = -4(x + 1)^2 + 2

<u>Question #7</u>

The vertex of the graph is

(h, k) = (2, 1)

So, we have:

y = a(x - 2)^2 + 1

The graph pass through (1, 3)

So, we have:

3 = a(1 - 2)^2 + 1

Evaluate the like terms

a = 2

Substitute a = 2 in y = a(x - 2)^2 + 1

y = 2(x - 2)^2 + 1

<u>Question #8</u>

The vertex of the graph is

(h, k) = (1, -2)

So, we have:

y = a(x - 1)^2 - 2

The graph pass through (0, -3)

So, we have:

-3 = a(0 - 1)^2 - 2

Evaluate the like terms

a = -1

Substitute a = -1 in y = a(x - 1)^2 - 2

y = -(x - 1)^2 - 2

Hence, the equations of the functions are y = -4(x + 1)^2 + 2, y = 2(x - 2)^2 + 1 and y = -(x - 1)^2 - 2

Read more about parabola at:

brainly.com/question/1480401

#SPJ1

5 0
2 years ago
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