Answer:
The expression that has a base is 3m⁴
Step-by-step explanation:
I hope it helps!!!
Answer:
(4^-3)(x^-3) y^(18)
or
y^18/ (64 x^3)
Step-by-step explanation:
(4xy^-6)^-3
Distribute the exponent to all terms in the parentheses
(4^-3)(x^-3) (y^-6)^-3
a^ b^c = a^ (b*c)
(4^-3)(x^-3) y^(-6*-3)
(4^-3)(x^-3) y^(18)
If we do not want negative exponents
a ^ -b = 1/ a^b
y^18/( 4^3 x^3)
y^18/ (64 x^3)
- Vertex/General Form: y = a(x - h)^2 + k, with (h,k) as the vertex
- (x + y)^2 = x^2 + 2xy + y^2
- Standard Form: y = ax^2 + bx + c
So before I put the equation into standard form, I'm first going to be putting it into vertex form. Since the vertex appears to be (-1,7), plug that into the vertex form formula:

Next, we need to solve for a. Looking at this graph, another point that is in this line is the y-intercept (0,5). Plug (0,5) into the x and y placeholders and solve for a as such:

Now we know that <u>our vertex form equation is y = -2(x + 1)^2 + 7.</u>
However, we need to convert this into standard form still, and we can do it as such:
Firstly, solve the exponent: 
Next, foil -2(x^2+2x+1): 
Next, combine like terms and <u>your final answer will be:
</u>
The answer to your question is: Yes, I think I could help".
Thank you for the points.
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(6^4 x 10^2) / (6^2 x 2^4)
Divide the numerator and denominator by 6^2 ,
(6^2 x 10^2) / (2^4)
6^2 = 36
10^2 = 100
2^4 = 16
Plug these equivalents into the fraction:
(36 x 100) / 16 = 3600 / 16 = <em>225 </em>.