Question

Find two consecutive odd intefers whose product is 63

Answer 1

Hello,

Let's assume 2n-1 the first integer
and 2n+1 the second.

(2n-1)*(2n+1)=64
(2n)²-1=64
4n²=64
n²=16
==>n=4 or n=-4
If n=-4 then 2n-1=2*(-4)-1=-9 and 2n+1=2*(-4)+1=-7
If n=4 then 2n-1=2*(4)-1=7 and 2n+1=2*(4)+1=9

(-9,-7) and (7,9) are the 2 solutions.

Answer 2

Two consecutive odd integers are known as back-to-back odd whole numbers; one right after the other.
For example; 1 and 3, 3 and 5, 5 and 7, and so on. Let’s work up to which two consecutive odd integers make a product of 63.
1 x 3 = 3; no
3 x 5 = 15; no
5 x 7 = 35; no
7 x 9 = 63; yes

From the work shown above, we can see that the two consecutive odd integers “7” and “9” make a product of 63.

I hope this helps!