Answer:
4/11
Step-by-step explanation:
Outcomes that meet your requirement are
(1, 6), (2, 6), (6, 1), (6, 2)
for a total of 4 favorable outcomes.
There are 11 outcomes in which one die shows a 6.
So your probability would be 4/11.
100
M = log(I/S)
The intensity of the first earthquake:
8 = log(I₁/S)
10⁸ = I₁/S
I₁ = 10⁸ S
The intensity of the second earthquake:
6 = log(I₂/S)
10⁶ = I₂/S
I₂ = 10⁶ S
The ratio is:
I₁/I₂ = (10⁸ S) / (10⁶ S)
I₁/I₂ = 100
It is 100 times stronger.
(foh)(6) = -29
(f o h)(6) is f(h(x)) when x = 6.
We have that:
f(x) = 4x - 1
h(x) = -x-1
f(h(x)) = 4(-x-1) - 1 = -4x - 4 - 1 = -4x - 5
(foh)(6) = -4(6) - 5 = -29
Solution given:
radius [r]=4
height [h]=5
we have
Surface area of cylinder=2πr(r+h)
=2π×4(4+5)
=<u>72πunits³ is a required volume.</u>
