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3 years ago

A sphere and a cylinder have the same radius and height. The volume of the cylinder is Amie found the volume of the sphere.

Mathematics

2 answers:

vredina [299]3 years ago

7 0

Answer:

The answer is the first

Amie should have multiplied 54 by 2/3

Step-by-step explanation:

* Lets start with the rule of the volume of each solid

∵ Volume the sphere = 4/3 π r³

∵ Volume the cylinder = π r² h

∵ The radii and the heights of the sphere and the cylinder are equal

∴ The ratio between there volumes are

4/3 π r³ : π r² h

- Lets divide each part by π r²

∴ 4/3 r : h

∵ The height of the sphere = the diameter of it = 2r

∴ The height of the cylinder = 2r

∴ The ratio will be:

4/3 r : 2r

- Now divide each part by 2r

∵ (4/3)r ÷ 2r = 2/3

∵ 2r ÷ 2r = 1

∴ The ratio is 2/3 : 1

∴ The volume of the sphere = 2/3 the volume of the cylinder

∵ The volume of the cylinder = 54 m³

∴ The volume of the sphere = 2/3 × 54 = 36 m³

∴ The answer is Amie should have multiplied 54 by 2/3

Elena L [17]3 years ago

4 0

Answer:

The answer is Amie should have multiplied 54 by 2/3

Step-by-step explanation:

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Which expression is equivalent to the expression below?(6c^2+3c/-4c+2)/(2c+1/4c-2)

algol [13]

Answer:

-3c

Step-by-step explanation:

The given expression is:

$\frac{\frac{6c^{2}+3c}{-4c+2}}{\frac{2c+1}{4c-2}}$

We need to simplify this expression. The rational expression in the denominator can be multiplied to numerator by taking its reciprocal as shown below:

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Thus, the given expression in simplified form is equal to -3c

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3 years ago

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An oil company fills 1 over 12 of a tank in 1 over 3 hour. At this rate, which expression can be used to determine how long will

Leto [7]

Don't let fractions fool you.

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3 years ago

Find the value of x for which m||n <br> A:38 B:62 C:103 D:150

Alecsey [184]

Answer:

I think the answer is B= 62

Step-by-step explanation:

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3 years ago

What would the graph of y=x look like? name three ordered pairs that lie on the line.

ololo11 [35]

-- The graph looks like a line that passes through the origin,
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-- Point #1 on the line:
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Rinse and repeat, as many times as you like,
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3 years ago

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a team of 10 players is to be selected from a class of 6 girls and 7 boys. match each scenario to its probability

mars1129 [50]

Step-by-step explanation:

The selection of r objects out of n is done in

many ways.

The total number of selections 10 that we can make from 6+7=13 students is

thus, the sample space of the experiment is 286

"The probability that a randomly chosen team includes all 6 girls in the class."

total number of group of 10 which include all girls is C(7, 4), because the girls are fixed, and the remaining 4 is to be completed from the 7 boys, which can be done in C(7, 4) many ways.

P(all 6 girls chosen)=35/286=0.12

"The probability that a randomly chosen team has 3 girls and 7 boys."

with the same logic as in A, the number of groups were all 7 boys are in, is

so the probability is 20/286=0.07

"The probability that a randomly chosen team has either 4 or 6 boys."

case 1: the team has 4 boys and 6 girls

this was already calculated in part A, it is 0.12.

case 2, the team has 6 boys and 4 girls.

there C(7, 6)*C(6, 4) ,many ways of doing this, because any selection of the boys which can be done in C(7, 6) ways, can be combined with any selection of the girls.

the probability is 105/286=0.367

since case 1 and case 2 are disjoint, that is either one or the other happen, then we add the probabilities:

0.12+0.367=0.487 (approximately = 0.49)

"The probability that a randomly chosen team has 5 girls and 5 boys."

selecting 5 boys and 5 girls can be done in

many ways,

so the probability is 126/286=0.44

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3 years ago