there are 6 terms in the simplified expression
Step-by-step explanation:
h(x) = 3. g(x) + 5
x= -1 h(x) = 3×8 + 5= 29
x= 0h(x) = 3×5 + 5= 20
x= 2 h(x) = 3×1 + 5= 8
x= 5 h(x) = 3×-5 + 5= -10
Answer:
<em>Factored Form: </em><em> </em><em>( y - 2 )( 3y + 7 )</em>
Step-by-step explanation:
<em>1. Let us first write down the problem at hand: </em>3y^2 + y - 14
<em>2. Now let us break this expression into groups: </em>
3y^2 - 6y + 7y - 14 ⇒ ( 3y^2 - 6y )( 7y - 14 )
<em>3. Factor 3y from 3y^2 - 6y:</em>
3y^2 - 6y ⇒ 3y( y - 2 )
<em>4. Factor 7 from 7y - 14:</em>
7y - 14 ⇒ 7( y - 2 )
<em>5. Substitute Step #3, 4 ⇒ Step #2:</em>
3y( y - 2 ) + 7( y - 2 )
<em>6. Factor common term y - 2:</em>
<em>Answer: ( y - 2 )( 3y + 7 )</em>
8,991 which is the product of 999 times 9
Assume the following:
Brad has been in the soccer team for b years.
Scot has been in the soccer team for s years.
"The number of years that brad has been on the soccer team is 2 less than 5 times the number of years that Scott has"
means: b=5s-2
"in total,the boys have been on the soccer team for 10 years."
means: b+s=10
so we have the equations:
i) b=5s-2
ii) b+s=10
substitute b in ii) with 5s-2, as they are equal, from i
(5s-2)+s=10
5s-2+s=10
6s=12
s=2,
then , from b+s=10, b=8
Answer: Brad has been in the team for 8 years.
