Classify each sequence as arithmetic, geometric, or neither by dragging it into the correct box.

Mathematics

1 answer:

Elena L [17]3 years ago

3 0

Answer:from crud v4v

Step-by-step explanation:

l rfnv u4hf u4ihfcfnoijn3

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What is the size of angle x ? <br> And give a reason

Serggg [28]

Answer:

x = 75°

Reason:

m∠EFG and m∠ABC are supplementary angles

8 0

3 years ago

IB QUESTIONS:

enyata [817]

Step-by-step explanation:

Using SOHCAHTOA

$\tan = \frac{opposite}{adjacent} \\ \tan {31}^{0} = \frac{450}{x} \\ \tan {31}^{0} = 0.6009 \\ 0.6009 = \frac{450}{x} \\ cross \: multiply \\ 0.6009x = 450 \\ divide \: both \: sides \: by \: 0.6009 \\ x = \frac{450}{0.6009}x \\ = 748.9$

Second Question Explanation:

a. The base angles of an isosceles triangle are equal so angle ABC is also 32°

but the sum of angles in a triangle = 180° therefore

let angle CAB be x

${32}^{0} + {32}^{0} + {x}^{0} = {180}^{0} \\ 64 + x = 180 \\ {x}^{0} = 180 - 64 \\ {x}^{0} = {116}^{0}$

b. If you share a triangle in half you get 2 right angles so I'll use SOHCAHTOA to find the length AB

First the base of the right angled triangle will be 20/2 = 10

$\cos = \frac{adjacent}{hypotenuse} \\ \cos {32}^{0} = \frac{10}{ab} \\ \cos32 = 0.8480 \\ 0.8480 = \frac{10}{ab} \\ ab = \frac{10}{0.8480} \\ line \: ab = 11.8$

c. To find the are we'll need to get the height first

using the right angled triangle With base 10cm and hypotenuse 11. 8 to find the height we'll use the Pythagorean theorem

${(11.8)}^{2} = {x}^{2} + {10}^{2} \\ 1324.24 = {x}^{2} + 100 \\ {x}^{2} = 139.24 - 100 \\ {x}^{2} = 39.24 \\ \sqrt{ {x}^{2} } = \sqrt{39.24} \\ x = \sqrt{39.24 } \\ x = 6.3$

now to find the area

$area \: of \: triangle = \frac{1}{2} \times base \times height \\ = \frac{1}{2} \times 20 \times 6.3 \\ \frac{20 \times 6.3}{2} \\ = \frac{126}{2} \\ 63 {cm}^{2}$

4 0

3 years ago

To find the height of a pole, a surveyor moves 120 feet away from the base of the pole and then, with a transit 8 feet tall, mea

Vikki [24]

Refer to the figure.
Let AB be the height of the pole; CD be the height of the transit; BC is the distance from the base of the pole to the transit.

Triangle ADE is a right triangle with angle D measuring 26 degrees. Using the tangent function, we have
$tan\:26^{\circ} =\frac{AE}{120}$
So,
$AE=120\:tan\:26^{\circ}$
$AE=58.53\:$

Therefore, the overall height of the pole is
$AB=58.53+8=66.53\:feet$

The height of the pole is 66.53 feet.