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2 years ago

the derivative of a sum of two functions is different than the sum of the derivatives of thw two functions?

Mathematics

1 answer:

Maru [420]2 years ago

3 0

Answer:

Step-by-step explanation:

False.

g(x) = f1(x) + f2(x)

then

g'(x) = f1'(x) + f2'(x),

i.e.

the derivative of a sum equals the sum of the derivatives.

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Can I please have help with question 2) a and b

Ulleksa [173]

Answer:

$\frac{10\sqrt{6} }{3}$ and $\frac{11\sqrt{3} }{3}$

Step-by-step explanation:

(a)

A = $\frac{1}{2}$ × 4 $\sqrt{2}$ × $\frac{5}{\sqrt{3} }$

= 2 $\sqrt{2}$ × $\frac{5}{\sqrt{3} }$

= $\frac{10\sqrt{2} }{\sqrt{3} }$ × $\frac{\sqrt{3} }{\sqrt{3} }$ ← rationalise the denominator

= $\frac{10\sqrt{6} }{3}$ units²

(b)

Using Pythagoras' identity in the right triangle

let hypotenuse be h , then

h² = (4 $\sqrt{2}$ )² + ( $\frac{5}{\sqrt{3} }$ )²

= 32 + $\frac{25}{3}$

= $\frac{96}{3}$ + $\frac{25}{3}$

= $\frac{121}{3}$ ( take the square root of both sides )

h = $\sqrt{\frac{121}{3} }$ = $\frac{11}{\sqrt{3} }$ × $\frac{\sqrt{3} }{\sqrt{3} }$ ← rationalise the denominator

h = $\frac{11\sqrt{3} }{3}$

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2 years ago

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hodyreva [135]

Answer:

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3 years ago

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Answer:

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2 years ago

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2 years ago

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