<span>so we want to know the vertex point of the equation f(x)=-(x+8)(x-14). First lets simplify the equation: f(x)=-x^2+6x+112. Now lets calculate the vertex by transforming the function to the form: f(x)=a(x-h)^2 + k where h and k are vertex coordinates. So: f(x)= (-x^2+6x+9)+121=-(x-3)^2+121 and the vertex point is (3,121).</span>
first you start with y=mx+b find the y intercept first which is 1 next you just count down the block which is 3 then count to the right till you find a spot where it lands which would get you y=3/4+1
