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3 years ago

What is twice the sum of 4x^2-x+1 and -6x^2+x-4 ?

Mathematics

2 answers:

pantera1 [17]3 years ago

8 0

Answer:

-4x^2 - 6

Step-by-step explanation:

When you add them together it gives a sum of -2x^2 - 6. Multiplying that by 2 gives you the above answer.

lesantik [10]3 years ago

6 0

-4x^2 - 6

When you add them together it gives a sum of -2x^2 - 6. Multiplying that by 2 gives you the above answer.

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A store buys 13 sweaters for $52 and sells them for $377. How much profit does the store make per sweater?

elena-s [515]

Answer:

Step-by-step explanation:

So, 13 sweaters cost $52, so 1 sweater costs $4. If he sells the 13 sweaters for $377, you will need to do 377 divided by 13, and that is 29. The last step you have to do is find the difference (subtraction) of 4 and 29. So, 29-4=25. Therefore, The profit the store made was $25 per sweater. Hoped that helped!!

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2 years ago

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Scientists are preparing two satellites to be launched. The equation y = 8000.C represents the number of miles, y, that the sate

Tema [17]

Answer: 6800

Step-by-step explanation:

24000 divided into 20

8000-1200

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2 years ago

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Find the highest common factor (HCF) of 12 and 20.

damaskus [11]

<span>The factors of are 12, 6, 4, 3, 2, 1, while those for 20 are 20, 10, 5, 4, 2, 1. The common highest factor for the two numbers is 4.</span>

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3 years ago

You are planning a promotion that will feature breakfast sandwiches. Your store normally sells 75 breakfast sandwiches per week.

EleoNora [17]

The number of additional sandwiches is 15.

If we multiply 75 sandwiches by 0.2 (20%), then we get 15, which would be the number of sandwiches needed to be sold to meet the sales goal.

Hope this helped.

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2 years ago

Find all the zeros of the equation x^4-6x^2-7x-6=0

rusak2 [61]

Answer:

The zeros are

$x=-2,\:x=3,\:x=-\frac{1}{2}+i\frac{\sqrt{3}}{2},\:x=-\frac{1}{2}-i\frac{\sqrt{3}}{2}$

Step-by-step explanation:

We have been given the equation x^4-6x^2-7x-6=0

Use rational root theorem, we have

$a_0=6,\:\quad a_n=1$

$\mathrm{The\:dividers\:of\:}a_0:\quad 1,\:2,\:3,\:6,\:\quad \mathrm{The\:dividers\:of\:}a_n:\quad 1$

$\mathrm{Therefore,\:check\:the\:following\:rational\:numbers:\quad }\pm \frac{1,\:2,\:3,\:6}{1}$

$-\frac{2}{1}\mathrm{\:is\:a\:root\:of\:the\:expression,\:so\:factor\:out\:}x+2$

$=\left(x+2\right)\frac{x^4-6x^2-7x-6}{x+2}\\$

$=x^3-2x^2-2x-3$

Again factor using the rational root test, we get

$=\left(x+2\right)\left(x-3\right)\left(x^2+x+1\right)$

Using the zero product rule, we have

$x+2=0:\quad x=-2\\x-3=0:\quad x=3\\x^2+x+1=0\\\\x_{1,\:2}=\frac{-1\pm \sqrt{1^2-4\cdot \:1\cdot \:1}}{2\cdot \:1}\\\\=-\frac{1}{2}+i\frac{\sqrt{3}}{2},\:x=-\frac{1}{2}-i\frac{\sqrt{3}}{2}$

Therefore, the zeros are

$x=-2,\:x=3,\:x=-\frac{1}{2}+i\frac{\sqrt{3}}{2},\:x=-\frac{1}{2}-i\frac{\sqrt{3}}{2}$

4 0

3 years ago

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