To solve this problem, we need to first find the dimensions of the side of the blue and purple squares.
We're given that the purple (smaller) square has a side length of x inches.
We are also given that the blue band has a width of 5 inches.
Since the blue band surrounds the purple square on both sides, the length of the blue square is x+2(5)=x+10 inches.
The net area of the band is therefore the difference of the area of the blue square and the purple square, namely take out the area of the purple square from the blue.
Therefore
Area of band

[recall



or 20(x+5) if you wish.
(9x - 7) - (5x + 10 )
2x - 15x
- 13x
The y intercept is 3
You can also say that the y intercept is at (0,3) which is a more detailed answer. However saying "y intercept is 3" is sufficient enough because the x coordinate of the y intercept is always x = 0.
The y intercept is the location where the graph crosses or touches the y axis. This is at the halfway point between the 2 and 4, so (2+4)/2 = 6/2 = 3
There are 48 possible outcomes in this situation, and of those outcomes, the ones whose sums are a multiple of three are;
12, 21, 15, 51, 24, 42, 33, 18, 27, 36, 63, 45, 54, 48, 57, and 66. So, that is 16 out of 48 possibilities, or 16/48, which simplifies to 1/3. Written as a percent, the probability of getting numbers whose sum is a multiple of three is 33.33%.
Hope this is helpful! :)