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Vitek1552 [10]
3 years ago
15

Solve pls brainliest

Mathematics
2 answers:
emmasim [6.3K]3 years ago
5 0

Answer:

28.5

Step-by-step explanation:

1/2 is 0.5 as a decimal.

That would mean that 28 1/2 is the same as 28.5.

Hope this helps! Brainliest would be really appreciated!

Gnoma [55]3 years ago
3 0
28.5. Pls brainliest
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Answer: The correct option is A, itis the product of the initial population and the growth factor after h hours.

Explanation:

From the given information,

Initial population = 1000

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Total population after h hours is,

1000(1+0.3)^h

It is in the form of,

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Where P_0(t) is the initial population, r is increasing rate, t is time and [tex(1+r)^t[/tex]  is the growth factor after time t.

In the above equation 1000 is the initial population and (1+0.3)^h is the growth factor after h hours. So the equation is product of of the initial population and the growth factor after h hours.

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If Logan has $30.67 and Jenny has $12.69 how much more does Logan have than Jenny
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A hiker starting at point P on a straight road wants to reach a forest cabin that is 2 km from a point Q, 3 km down the road fro
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Step-by-step explanation:

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-3 = 4(13 − 6x + x²)^-½ (-6 + 2x)

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576 − 384x + 64x² = 117 − 54x + 9x²

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7 0
3 years ago
the height h(t) of a trianle is increasing at 2.5 cm/min, while it's area A(t) is also increasing at 4.7 cm2/min. at what rate i
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Answer:

The base of the triangle decreases at a rate of 2.262 centimeters per minute.

Step-by-step explanation:

From Geometry we understand that area of triangle is determined by the following expression:

A = \frac{1}{2}\cdot b\cdot h (Eq. 1)

Where:

A - Area of the triangle, measured in square centimeters.

b - Base of the triangle, measured in centimeters.

h - Height of the triangle, measured in centimeters.

By Differential Calculus we deduce an expression for the rate of change of the area in time:

\frac{dA}{dt} = \frac{1}{2}\cdot \frac{db}{dt}\cdot h + \frac{1}{2}\cdot b \cdot \frac{dh}{dt} (Eq. 2)

Where:

\frac{dA}{dt} - Rate of change of area in time, measured in square centimeters per minute.

\frac{db}{dt} - Rate of change of base in time, measured in centimeters per minute.

\frac{dh}{dt} - Rate of change of height in time, measured in centimeters per minute.

Now we clear the rate of change of base in time within (Eq, 2):

\frac{1}{2}\cdot\frac{db}{dt}\cdot h =  \frac{dA}{dt}-\frac{1}{2}\cdot b\cdot \frac{dh}{dt}

\frac{db}{dt} = \frac{2}{h}\cdot \frac{dA}{dt} -\frac{b}{h}\cdot \frac{dh}{dt} (Eq. 3)

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b = \frac{2\cdot (130\,cm^{2})}{15\,cm}

b = 17.333\,cm

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The base of the triangle decreases at a rate of 2.262 centimeters per minute.

6 0
3 years ago
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