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AlladinOne [14]
3 years ago
14

Solve x 2 + 6x - 5 = 0 by completing the square. Which equation is used in the process?

Mathematics
1 answer:
ella [17]3 years ago
8 0

x ^2 + 6x - 5 = 0\\\\ x^2+6x+9-14=0\\\\ (x+3)^2=14\\\\ x+3=\sqrt{14} \vee x+3=-\sqrt{14}\\\\ x=-3+\sqrt{14} \vee x=-3-\sqrt{14}

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Answer:

Step-by-step explanation:

a) \int\limits^{\infty} _1 {\frac{1}{n^4} } \, dn\\ =\frac{n^{-3} }{-3}

Substitute limits to get

= \frac{1}{3}

Thus converges.

b) 10th partial sum =

\int\limits^{10} _1 {\frac{1}{n^4} } \, dn\\ =\frac{n^{-3} }{-3}

=\frac{-1}{3} (0.001-1)\\= 0.333

c) Z [infinity] n+1 1 /x ^4 dx ≤ s − sn ≤ Z [infinity] n 1 /x^ 4 dx, (1)

where s is the sum of P[infinity] n=1 1/n4 and sn is the nth partial sum of P[infinity] n=1 1/n4 .

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3 0
3 years ago
Kalvin sells bottles of water at baseball games he pays 0.75 per bottle and 3.78 for the ice to keep cold let b represent the nu
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Answer:

3.78+.75b=c

Step-by-step explanation:

7 0
3 years ago
In Part C, you determined that the proper ratio of packages of buns, packages of patties, and jars of pickles is 3:2:4. If you w
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Answer: packages of buns: 100

              packages of patties: 67

               jars of pickles: 133

(100,67,133)

Step-by-step explanation: packages of buns: B

                                            packages of patties: P

                                            jars of pickles: J

B:P:J = 3:2:4

B + P + J = 300

Let x be the number we must multiply the numbers to obtain the quantity and keep the ratio.

Bx + Px + Jx = 300

3x + 2x + 4x = 300

x = 300/9

So,

3.300/9 = 100

2.300/9 = 66.6666

4.300/9 = 133.333

As we cannot buy 0.666 or 0.33 of patties and pickles, we round up

So: packages of buns: 100

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               jars of pickles: 133

7 0
3 years ago
The hyperbolic orbit of a comet is represented on a coordinate plane with center at (0, 4). One branch has a vertex at (0, 10) a
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Remember that

If the given coordinates of the vertices and foci have the form (0,10) and (0,14)

then

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so

the equation is of the form

(y-k)^2/a^2-(x-h)^2/b^2=1

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center (h,k) is equal to (0,4)

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a=10-4=6

(0,c-k) is equal to (0,14)

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the equation is equal to

<h2>(y-4)^2/36-x^2/64=1</h2><h2>the answer is option A</h2>
6 0
1 year ago
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Answer:

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Step-by-step explanation:

6 0
3 years ago
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