Answer:
Step-by-step explanation:
a) 
Substitute limits to get
= 
Thus converges.
b) 10th partial sum =

=
c) Z [infinity] n+1 1 /x ^4 dx ≤ s − sn ≤ Z [infinity] n 1 /x^ 4 dx, (1)
where s is the sum of P[infinity] n=1 1/n4 and sn is the nth partial sum of P[infinity] n=1 1/n4 .
(question is not clear)
Answer: packages of buns: 100
packages of patties: 67
jars of pickles: 133
(100,67,133)
Step-by-step explanation: packages of buns: B
packages of patties: P
jars of pickles: J
B:P:J = 3:2:4
B + P + J = 300
Let x be the number we must multiply the numbers to obtain the quantity and keep the ratio.
Bx + Px + Jx = 300
3x + 2x + 4x = 300
x = 300/9
So,
3.300/9 = 100
2.300/9 = 66.6666
4.300/9 = 133.333
As we cannot buy 0.666 or 0.33 of patties and pickles, we round up
So: packages of buns: 100
packages of patties: 67
jars of pickles: 133
Remember that
If the given coordinates of the vertices and foci have the form (0,10) and (0,14)
then
the transverse axis is the y-axis
so
the equation is of the form
(y-k)^2/a^2-(x-h)^2/b^2=1
In this problem
center (h,k) is equal to (0,4)
(0,a-k)) is equal to (0,10)
a=10-4=6
(0,c-k) is equal to (0,14)
c=14-4=10
Find out the value of b
b^2=c^2-a^2
b^2=10^2-6^2
b^2=64
therefore
the equation is equal to
<h2>(y-4)^2/36-x^2/64=1</h2><h2>the answer is option A</h2>
Answer:
15/61+18/61i
Step-by-step explanation: