The total number of sweets given to Mohamed in the beginning is equals to 20.
As given in the question,
Let x be the total number sweets given to Mohamed in the beginning.
Number of sweets he ate when feeling sick =
Number of sweets left = x - (x /5)
= (4x / 5)
Number of sweets he ate next day = ×
= x /5
Number of sweets left = (4x/5) - (x/5)
= (3x /5)
Number of sweets he ate on the following day = ×
= (3x / 20)
Number of sweets left at the end = (3x /5) - (3x/20)
= (12x-3x) / 20
= (9x /20)
As per given condition,
(9x / 20) = 9
⇒ x = (9 × 20)/9
⇒ x= 20
Therefore, the total number of sweets given to Mohamed in the beginning is equals to 20.
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Answer:
a
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Answer:
We know our answer is correct because 11 + 12 + 13 equals 36 as displayed Below
Explanation
3X + 3 = 36 3X + 3 - 3 = 36 - 3 3X = 33 3X/3 = 33/3 X = 11 Which means that the first number is 11, the second number is 11 + 1 and the third number is 11 + 2. Therefore, three consecutive integers that add up to 36 are 11, 12, and 13. 11 + 12 + 13 = 36 We know our answer is correct because 11 + 12 + 13 equals 36 as displayed above. Therefore, three consecutive integers that add up to 36 are 11, 12, and 13. 11 + 12 + 13 = 36
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Answer:
Yes, because 7/11 is greater than 1/11