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blondinia [14]
3 years ago
15

Cna anyone help with this one for me? I’ll give 5 stars

Mathematics
2 answers:
Elis [28]3 years ago
5 0

Answer:

D

Step-by-step explanation:

Nastasia [14]3 years ago
3 0
The answer would be C 3d + 8 is less than or equal to 35.

The tank holds no more than 35, so there can be 35 fish in the tank so it can be equal to 35.

there is already 8 fish from the old aquarium and there are 3 new fish per day so the 3 gets the variable
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What is the domain and range <br> f(x)=x^3
Wittaler [7]

Answer:

Step-by-step explanation:

The domain is X value and range is Y so just put y=x^3 in desmos and the graph appears then check its range and domain from it. the range is positive and nevative infinity

6 0
3 years ago
Can someone help me match these too?
Furkat [3]

ANSWER:

A is number 3

B is number 2

Step-by-step explanation:

The left side is A and B (order)

the right side is 1,2,3,4 (order)

explanation: A is number 3 because as said in A the tram already has 5 people which is what we start with a1 = 5 and we add 11 at each stop as shown in the equation.

B is number 2 for the same reason as it started with 2 but added 4 inches of rain each time.

7 0
3 years ago
I need help with 4 and 6
insens350 [35]
Im not sure about 6 but i think 4 is idk
6 0
3 years ago
Find the quotient: 8 ÷ 0.5
podryga [215]
The quotient is 16. Because 16 0.5s go into 8
6 0
3 years ago
Read 2 more answers
Let ​ f(x) = 4(x^2) - 3x
posledela

Answer:

(f+g)(x)=5x²-4x+3

(f-g)(x)=3x²-2x+3

(fg)(x)=4x^4-7x^3+15x^2-9x

\frac{f}{g}(x) =\frac{4x^2-3x}{x^2-x+3}

Step-by-step explanation:

Given that,

f(x)=4x²-3x

g(x)=x²-x+3

(f+g)(x)

=f(x)+g(x)

=4x²-3x+x²-x+3

=(4x²+x²)+(-3x-x)+3   [ combined the like terms]

=5x²-4x+3

(f-g)(x)

=f(x)-g(x)

=4x²-3x-(x²-x+3)

=4x²-3x-x²+x-3

=(4x²-x²)+(-3x+x)-3   [ combined the like terms]

=3x²-2x+3

(fg)(x)

=f(x).g(x)

=(4x²-3x).(x²-x+3)

=4x²(x²-x+3)-3x(x²-x+3)

=4x^4-4x^3+12x^2-3x^3+3x^2-9x

=4x^4+(-4x^3-3x^3)+(12x^2+3x^2)-9x

=4x^4-7x^3+15x^2-9x

\frac{f}{g}(x)

=\frac{f(x)}{g(x)}

=\frac{4x^2-3x}{x^2-x+3}

7 0
3 years ago
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