To answer this item, we are to multiply the given amount of wood that Jake can carry which is given to be 6 1/4 by the number of times his father can which is equal to 1 5/7. x = (6 1/4)(1 5/7)
x = 75/7
Thus, Jake's father can carry 10 5/7 pounds of wood. (I've had this question before btw)
13.
(a)
for x = 2:
for x = 5
(b)
The graph is:
(c)
Using the graph:
Using the quadratic formula:
![\begin{gathered} x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a} \\ x=\frac{-21\pm\sqrt[]{21^2-4(-5)(-10)}}{2(-5)} \\ x=\frac{-21\pm\sqrt[]{241}}{-10} \\ x=0.54758 \\ or \\ x=3.6524 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20x%3D%5Cfrac%7B-b%5Cpm%5Csqrt%5B%5D%7Bb%5E2-4ac%7D%7D%7B2a%7D%20%5C%5C%20x%3D%5Cfrac%7B-21%5Cpm%5Csqrt%5B%5D%7B21%5E2-4%28-5%29%28-10%29%7D%7D%7B2%28-5%29%7D%20%5C%5C%20x%3D%5Cfrac%7B-21%5Cpm%5Csqrt%5B%5D%7B241%7D%7D%7B-10%7D%20%5C%5C%20x%3D0.54758%20%5C%5C%20or%20%5C%5C%20x%3D3.6524%20%5Cend%7Bgathered%7D)
The greatest common factor is found by finding the product of common primes.
91=7*13, 104=2*2*2*13 so the gcf of 91 and 104 is 13. Since the highest power of x and y in both terms is 1, the hcf for the variables is just xy
13xy
Answer:
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Step-by-step explanation:
