Help? Please?? (There's a photo)

arlik [135]

I think its $32^(-2)$

4 0

3 years ago

Setup a rational equation and solve it from the word problem. Mr. Solberg can ride his scooter 3 miles against the wind in the s

dolphi86 [110]

Answer:

The speed of Mr Solberg's scooter when there is no wind is 35 miles per hour

Step-by-step explanation:

The given parameters are;

The time Mr. Solberg rides his scooter and cover 3 miles against the wind = The time Mr. Solberg rides his scooter and cover 4 miles with the wind

The speed of the wind = 5 miles per hour

Let v, represent the speed of Mr Solberg's scooter when there is no wind, we have;

Time = Distance/Speed

Mr Solberg's speed against the wind = v - 5

Mr Solberg's speed with the wind = v + 5

The distance covered at a given time, while riding against the wind = 3 miles

The distance covered at the same time, while riding with the wind = 4 miles

The time in both instances are therefore 3/(v - 5) = 4/(v + 5)

From which we have;

3 × (v + 5) = 4 × (v - 5)

3·v + 15 = 4·v - 20

20 + 15 = 4·v - 3·v

4·v - 3·v = 20 + 15

v = 35

The speed of Mr Solberg's scooter when there is no wind = v = 35 miles per hour.

7 0

3 years ago

Let's use the results of the 2012 presidential election as our x0. Looking up the popular vote totals, we find that our initial

gavmur [86]

Answer:

Step-by-step explanation:

Step-by-step explanation:

The code for the problem is as follows:

%Defining the given matrices:

%P is the matrix showing the percentage of changes in voterbase

P = [ 0.8100 0.0800 0.1600 0.1000;

0.0900 0.8400 0.0500 0.0800;

0.0600 0.0400 0.7400 0.0400;

0.0400 0.0400 0.0500 0.7800];

%x0 is the vector representing the current voterbase

x0 = [0.5106; 0.4720; 0.0075; 0.0099];

%In MATLAB, the power(exponent) operator is defined by ^

%After 3 elections..

x3 = P^3 * x0;

disp("The voterbase after 3 elections is:");

disp(x3);

%After 6 elections..

x3 = P^6 * x0;

disp("The voterbase after 6 elections is:");

disp(x3);

%After 10 elections..

x10 = P^10 * x0;

disp("The voterbase after 10 elections is:");

disp(x10);

%After 30 elections..

x30 = P^30 * x0;

disp("The voterbase after 30 elections is:");

disp(x30);

%After 60 elections.

x60 = P^60 * x0;

disp("The voterbase after 60 elections is:");

disp(x60);

%After 100 elections.

x100 = P^100 * x0;

disp("The voterbase after 100 elections is:");

disp(x100);

<u>The output is as well as the code in the matlab is as attached.</u>

The output will be as follows:

The voter-base after 3 elections is therefore:

0.392565, 0.400734, 0.109855, 0.096846

The voter-base after 6 elections is therefore:

0.36168, 0.36294, 0.14176, 0.13362

The voter-base after 10 elections is therefore:

0.35405, 0.34074, 0.15342, 0.15178

The voter-base after 30 elections is therefore:

0.35463, 0.32854, 0.15697, 0.15986

The voter-base after 60 elections is therefore:

0.35465, 0.32849, 0.15698, 0.15988

The voter-base after 100 elections is therefore:

0.35465, 0.32849, 0.15698, 0.15988

5 0

3 years ago

In the diagram the radius of the outer circle is 2x cm and the radius of the inner circle is 6 cm. The area of the shaded region

stich3 [128]

let's find the area of the outer circle and the inside circle

the inside's circle area

A= π x 6²=36π

the outer's

A' = π x 4x²= 4πx²

A'-A=4πx²- 36π=160πcm² equivalent to x²- 9=40, so x²=49 implies x =sqrt(49)=7, x=7.

5 0

3 years ago

How do you find the arc length of the partial circle.

sesenic [268]

Answer:

To find arc length, start by dividing the arc's central angle in degrees by 360. Then, multiply that number by the radius of the circle. Finally, multiply that number by 2 × pi to find the arc length i hope this helps!

6 0

3 years ago