3 years ago

Plz help asap help will appreiciated

1 answer:

5 0

The answer is (if going by letters A-D) D

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Tems11 [23]

It would be an open circle with an arrow going to the right

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3 years ago

yawa3891 [41]

$\displaystyle\lim_{\Delta x\to0}\frac{(x+\Delta x)^2-3(x+\Delta x)+2-(x^2-3x+2)}{\Delta x}$

Expand the numerator as

$x^2+2x\Delta x+(\Delta x)^2-3x-3\Delta x+2-x^2+3x-2=(2x-3)\Delta x+(\Delta x)^2$

Then in the limit,

$\displaystyle\lim_{\Delta x\to0}\frac{(2x-3)\Delta x+(\Delta x)^2}{\Delta x}=\lim_{\Delta x\to0}(2x-3+\Delta x)=\boxed{2x-3}$

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2 years ago

balu736 [363]

I believe that the a value is 2

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3 years ago

Gre4nikov [31]

I believe all the integers are: -9, 0, 1,345, -5, and 129

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2 years ago

soldier1979 [14.2K]

C: y=-2x+1 and d: y=x-3

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2 years ago