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frosja888 [35]
3 years ago
12

What are the first three terms of the sequence modeled by the recursive function an=1/2an-1 when a1=1?

Mathematics
2 answers:
Goshia [24]3 years ago
7 0

Answer:

A

Step-by-step explanation:

loris [4]3 years ago
6 0

Answer:

Option A is correct that is 1,\frac{1}{2},\frac{1}{4}

Step-by-step explanation:

We have been given a formula a_n=\frac{1}{2}\cdot a_n-1

a_1=1

We will put values of n in a_n=\frac{1}{2}\cdot a_n-1

when n=2 we get

a_2=\frac{1}{2}\cdot a_2-1

\Rightarrow a_2=\frac{1}{2}\cdot a_1

\Rightarrow a_2=\frac{1}{2}\cdot 1

\Rightarrow a_2=\frac{1}{2}

when n=3

a_3=\frac{1}{2}\cdot a_2

\Rightarrow a_3=\frac{1}{2}\cdot \frac{1}{2}

\Rightarrow a_3=\frac{1}{4}

Therefore, Option A is correct that is 1,\frac{1}{2},\frac{1}{4}

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Answer:

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c. 570

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Step-by-step explanation:

Given the graph is a bell - shaped curve. So, we understand that this is a normal distribution and that the bell - shaped curve is a symmetric curve.

Please refer the figure for a better understanding.

a. In a normal distribution, Mean = Median = Mode

Therefore, Median = Mean = 72

b. We have to know that 68% of the values are within the first standard deviation of the mean.

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Scores between 63 and 81 :

Note that 72 - 9 = 63 and

72 + 9 = 81

This implies scores between 63 and 81 constitute 68% of the values, 34% each, since the curve is symmetric.

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That means 816 students have scored between 63 and 81.

c. We have to know that 95% of the values lie between second Standard Deviation of the mean.

i.e., 95% values are between Mean $ \pm $ 2(SD).

Note that 90 = 72 + 2(9) = 72 + 18

Also, 54 = 63 - 18.

Scores between 54 and 90 totally constitute 95% of the values. So, Scores between 72 and 90 should amount to $ \frac{95}{2} \% $ of the values.

Therefore, Scores between 72 and 90 = $ \frac{95}{2(100)} \times 1200 = \frac{95}{200} \times 1200  $

$ \implies 95 \times 12 $ = 570.

That is a total of 570 students scored between 72 and 90.

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Since, we are asked to find scores below 54. It should be 2.5% of the values.

So, Scores below 54 = $ \frac{2.5}{100} \times 1200 $

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That is, 30 students have scored below 54.

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