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harina [27]
3 years ago
14

Which picture shows the correct graph of |x|=3?

Mathematics
1 answer:
suter [353]3 years ago
8 0

Answer:

[see picture]

Step-by-step explanation:

There were no given choices, but I did graph the equation using Desmos.

Choose the answer that is closest to this:

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I need help I will give 40 points and Brainliest!!!!!!Finding the Slope of a Line from a Table
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Answer:

hmmmmm

Step-by-step explanation:

7 0
3 years ago
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What is the fraction of 3\4 of 28
pentagon [3]
If you are trying to find 3/4 of 28, multiply 3/4 (or 0.75( by 28), which equals 21.

3/4 • 28 = 21
3 0
4 years ago
a) The vertices A, B, C of a triangle are (2, -1, -3), (4, 2, 3) and (6, 3, 4) respectively. Show that AB = (2,3,6) and AC = 9.​
Sav [38]

Answer:

... a triangle are 2,-1,-3 4,2,3 and 6,3,4 respectively. If vector AB=2,3,6 vector AC=4,4,7 vector BC=2,1,1 , show that AB=7 AC=9 and BC= square root of 6.

7 0
3 years ago
A wooden jewelry box has the shape of a prism with a regular hexagonal base of 85.3 in2. The sides of the hexagonal base are all
Anna35 [415]

Answer:

792.9 in²

Step-by-step Explanation:

Given:

Area of the base of the regular hexagonal prism box (B) = 85.3 in²

Each side length of hexagonal base (s) = 5.73 in

Height of prism box (h) = 18.10 in

Required:

Surface area of the wood used in making the hexagonal prism box

SOLUTION:

Surface area for any given regular prism can be calculated using the following formula: (Perimeter of Base × height of prism) + 2(Base Area)

Perimeter of the hexagonal base of the prism box = 6(5.73) (Note: hexagon has 6 sides.)

Perimeter of base = 34.38 in

Height = 18.10 in

Base area is already given as 85.3 in²

Surface area of the hexagonal prism box = (34.38*18.10) + 2(85.3)

= 622.278 + 170.6 = 792.878 in^2

<em>Surface area of the wood used in making the jewelry box ≈ 792.9 in²</em>

3 0
3 years ago
Which combination of transformations can you use to show that one shape is congruent to another? A. dilations and reflections B.
lesya692 [45]

Question

Which combination of transformations can you use to show that one shape is congruent to another?

A. dilations and reflections

B. reflections and stretches

C. rotations and translations

D. reflections, dilations, and translations

E. rotations, translations, and dilationsANSWER -


ANSWER -

The correct answer to this is:

ROTATIONS AND TRANSLATIONS


Reflection and rotation can also be used but since their both grouped with dilations, they can't be used. When dilation is used, the size of the shape is changed and congruence won't be possible anymore . That's why the answer is the first option.




6 0
3 years ago
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