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White raven [17]
3 years ago
5

Find y when x=10. If y=8 when x=20.

Mathematics
2 answers:
ohaa [14]3 years ago
8 0
(x,y)
(10,y)
(20,8)
y=4
Misha Larkins [42]3 years ago
6 0
Y=4. Because half of 20 is 10 and half of 8 is 4. If this helps please consider answering my question.
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Using the given information, match the transformed equation from a parent function of <img src="https://tex.z-dn.net/?f=y%3Dx%5E
sergij07 [2.7K]

Step-by-step explanation:

The general form for a quadratic or cubic equation is:

y = a (x − h)ⁿ + k

If |a| is between 0 and 1, it's a vertical shrink.  If |a| is greater than 1, it's a vertical stretch.  If a is negative, there's a reflection over the x-axis.

h is the horizontal translation.  If h is positive, there's a translation to the right.  If h is negative, there's a translation to the left.  (Notice the expression in the parentheses is x − h, not x + h, so if it helps, rewrite the equation.)

k is the vertical translation.  If k is positive, there's a translation up.  If k is negative, there's a translation down.

f(x) = (x + 1)³ − 7

f(x) = 1 (x − -1)³ + -7

a = 1, h = -1, k = -7

This is y = x³ translated 1 unit to the left and 7 units down.

g(x) = -½ (x − 2)³

g(x) = -½ (x − 2)³ + 0

a = -½, h = 2, k = 0

This is y = x³ reflected over the x-axis, vertical shrink of ½, and translated 2 units to the right.

y = -(x − 4)³ − 2

y = -1 (x − 4)³ + -2

a = -1, h = 4, k = -2

This is y³ reflected over the x-axis, translated 4 units right and 2 units down.

5 0
3 years ago
Hi, I am a sub for Glenridge and I need the answer to the question as soon as possible please here is the question Carl is board
nignag [31]
35-4÷2 that is the answer
7 0
4 years ago
What is the measure of the unknown angle?
zaharov [31]

Answer:

The other angle is 100

Step-by-step explanation:

A straight line is 180, and if one angle is 80, then 180-80=100, giving you your answer. ^^

5 0
2 years ago
Read 2 more answers
How do you solve this?
lutik1710 [3]

\bf ~\hspace{7em}\textit{negative exponents} \\\\ a^{-n} \implies \cfrac{1}{a^n} ~\hspace{4.5em} a^n\implies \cfrac{1}{a^{-n}} ~\hspace{4.5em} \cfrac{a^n}{a^m}\implies a^na^{-m}\implies a^{n-m} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \cfrac{8^?}{8^3}=\cfrac{1}{8^8}\implies \cfrac{8^?}{8^3}=8^{-8}\implies 8^?=8^3\cdot 8^{-8}\implies 8^?=8^{3-8}\implies 8^?=8^{-5}


\bf \begin{array}{llll} \textit{if the bases are the same, for}\\ \textit{the equation to be true, the}\\ \textit{exponents must also be the same} \end{array}~\hspace{5em}?=-5 \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \cfrac{1}{r^3}=r^{-7}\cdot r^?\implies r^{-3}=r^{-7+?}\implies \stackrel{\textit{bases are the same, so are the exponents}}{-3=-7+?\implies 4=?}

7 0
3 years ago
PLEASE HURRY THIS IS DUE IN 20MIN
OverLord2011 [107]

This is not my answer I found it from another brainly

From the beginning we know we are dealing with two different rates. Distance is equal to (Speed X Time). We have two different speeds though. We will call the min speed = x and the max speed = y. With those two ideas in place we can make two equations for both Tony and Rae.

Tony:

2x+3.5y=355

Rae:

2x+3y=320

Now you can solve the equations by subtracting Rae's equation from Tony's

.5y=35 solve for y and you get 70

Now plug that y value back into either equation and you can solve for x. I'll use Rae's distance:

2x+3(70)=320

x=55

6 0
3 years ago
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