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White raven [17]
4 years ago
5

Find y when x=10. If y=8 when x=20.

Mathematics
2 answers:
ohaa [14]4 years ago
8 0
(x,y)
(10,y)
(20,8)
y=4
Misha Larkins [42]4 years ago
6 0
Y=4. Because half of 20 is 10 and half of 8 is 4. If this helps please consider answering my question.
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What is 90% of 20????
pickupchik [31]

Answer:

18

Step-by-step explanation:

Multiply 20 by 0.90 (that is 90%)

18 is the answer

Hope this helps :)

6 0
3 years ago
Read 2 more answers
The number of wrecks at a certain intersection varies directly as the number of cars that travel through the intersection. If th
Agata [3.3K]

Answer:

D. 245.

Step-by-step explanation:

If you take 1,085 cars and divide it by 31, and then take that answer and multiply it by 7 you get 245.

6 0
3 years ago
Which of these numbers is between 5/6 and 1?<br> (A) 4/5 <br> (B) 4/7 <br> (C)6/7
djverab [1.8K]
Two basic ways in which to do this problem:

1.  Find and apply the LCD.

2.  Convert all of the given numbers to their decimal form, to 2 or 3 places only.

Try #2 first:

5/6 = 0.83    

4/5 = 0.80 is not between 5/6 and 1.  Reject it.
4/7 = 0.57 Reject
6/7 = 0.86 This is between 5/6 and1.  This is the answer.

 
8 0
3 years ago
I have <img src="https://tex.z-dn.net/?f=%20%5Cfrac%7Bdx%7D%7Bdt%7D%20%3D%20%20%5Cfrac%7B5%7D%7Bx%7D%20" id="TexFormula1" title=
mojhsa [17]
\bf \cfrac{dx}{dt}=\cfrac{5}{t}\quad ,\quad x(0)=7\to &#10;\begin{cases}&#10;f(t)=0\\&#10;t=7&#10;\end{cases}\\\\&#10;-----------------------------\\\\&#10;\displaystyle \int \cfrac{5}{t}\cdot dt\implies 5\int \cfrac{1}{t}\cdot dt\implies 5ln|t|+C= f(t)&#10;\\\\\\&#10;\textit{now, we know when f(t)=0, t=7}\implies 5ln|7|+C=0&#10;\\\\\\&#10;C=-5ln(7)&#10;\\\\\\&#10;thus\implies \boxed{5ln|t|-5ln(7)=f(t)=x}

notice |7| 7 is positive, so we can simply remove the bars and use 7 by itself

6 0
3 years ago
How would I set up this problem?
Sliva [168]
Since in 1990 there are 28%, we need to figure out when it gets to 31%. In addition, since it increases by 0.6% every year, we can say that 0.6x+28 (since 28 is the base value) is the percentage of babies born in wedlock every year. Therefore, to get 0.6x+28=31, we subtract 28 from both sides to get 0.6x=3
Dividing both sides by 0.6, we get x=5=the amount of years it takes to get 31% of babies born in wedlock. Since 1990 is the base value (we start from there!), we add 5 to that to get 1990+5=1995 as the yar
4 0
3 years ago
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