9514 1404 393
Answer:
see attached
Step-by-step explanation:
The equation can be rewritten to vertex form, so you can tell the vertex is at (2, -5). The leading coefficient of 2 means the points will be twice as far apart vertically than they would be if the leading coefficient were 1. A couple of points are shown in the attached.
y = 2(x^2 -4x) +3
y = 2(x^2 -4x +4) +3 -8 . . . . . . complete the square
y = 2(x -2)^2 -5 . . . . . . . . . . . . finish putting in vertex form
G=2,0 I have notes
If u want I can explain
Answer:
Explanation: For this, it is often best to find the horizontal asymptote, and then take limits as x approaches the vertical asymptote and the end behaviours.
Well, we know there will be a horizontal asymptote at y = 0, because as x approaches infinite and negative infinite, the graph will shrink down closer and closer to 0, but never touch it. We call this a horizontal asymptote.
So we know that there is a restriction on the y-axis.
Now, since we know the end behaviours, let's find the asymptotic behaviours.
As x approaches the asymptote of 7⁻, then y would be diverging out to negative infinite.
As x approaches the asymptote at 7⁺, then y would be diverging out to negative infinite.
So, our range would be:
You can converte them to a common denominator like 6. 1/2 would be 3/6. 2/3 would be 4/6.
I believe the answer is A.
hope I helped
