The answers to the given addition operations are
7) 6 Hundredths add to 4 tenths add to 6 ones is equal to 6.46
8) 82 Hundredths add to 9 tenths add to 4 tens is equal to 41.72
<h3>Addition operation </h3>
From the question, we are to add the given numbers
7. 6 Hundredths add to 4 tenths add to 6 ones is equal to
6 Hundredths = 0.06
4 tenths = 0.4
6 ones = 6
Thus, we get
0.06 + 0.4 + 6 = 6.46
8. 82 Hundredths add to 9 tenths add to 4 tens is equal to
82 Hundredths = 0.82
9 tenths = 0.9
4 tens = 40
Thus, we get
0.82 + 0.9 + 40 = 41.72
Hence, the answers to the given addition operations are
7) 6 Hundredths add to 4 tenths add to 6 ones is equal to 6.46
8) 82 Hundredths add to 9 tenths add to 4 tens is equal to 41.72
Learn more on Addition operation here: brainly.com/question/4248979
#SPJ1
Answer:
$64 is the answer
Step-by-step explanation:
If I am correct the x and y values are the ones values of the overall $60 so if you on the x axis to where the 6 is it matches up with the 4 on the y axis so therefore the answer must be $64.
I hope this helps
<span>The solution to the equation 2/3 A= -24 is the coordinate of point A.
2/3 A = -24
A = -24 / 2/3
A = -24 * 3/2
A = -72/2
A = -36
The solution to the equation 20=-b/0.5 is the coordinate of point B
20 = -b/0.5
20 * 0.5 = -b
10 = -b
10/-1 = -b/-1
-10 = b
A = -36 and B = -10
The distance between the two letters is 26 units. </span>
Given:
![(ax+2)(bx+7)=15x^2+cx+14](https://tex.z-dn.net/?f=%28ax%2B2%29%28bx%2B7%29%3D15x%5E2%2Bcx%2B14)
And
![a+b=8](https://tex.z-dn.net/?f=a%2Bb%3D8)
Required:
To find the two possible values of c.
Explanation:
Consider
![\begin{gathered} (ax+2)(bx+7)=15x^2+cx+14 \\ abx^2+7ax+2bx+14=15x^2+cx+14 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20%28ax%2B2%29%28bx%2B7%29%3D15x%5E2%2Bcx%2B14%20%5C%5C%20abx%5E2%2B7ax%2B2bx%2B14%3D15x%5E2%2Bcx%2B14%20%5Cend%7Bgathered%7D)
So
![\begin{gathered} ab=15-----(1) \\ 7a+2b=c \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20ab%3D15-----%281%29%20%5C%5C%207a%2B2b%3Dc%20%5Cend%7Bgathered%7D)
And also given
![a+b=8---(2)](https://tex.z-dn.net/?f=a%2Bb%3D8---%282%29)
Now from (1) and (2), we get
![\begin{gathered} a+\frac{15}{a}=8 \\ \\ a^2+15=8a \\ \\ a^2-8a+15=0 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20a%2B%5Cfrac%7B15%7D%7Ba%7D%3D8%20%5C%5C%20%20%5C%5C%20a%5E2%2B15%3D8a%20%5C%5C%20%20%5C%5C%20a%5E2-8a%2B15%3D0%20%5Cend%7Bgathered%7D)
![a=3,5](https://tex.z-dn.net/?f=a%3D3%2C5)
Now put a in (1) we get
![\begin{gathered} (3)b=15 \\ b=\frac{15}{3} \\ b=5 \\ OR \\ b=\frac{15}{5} \\ b=3 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20%283%29b%3D15%20%5C%5C%20b%3D%5Cfrac%7B15%7D%7B3%7D%20%5C%5C%20b%3D5%20%5C%5C%20OR%20%5C%5C%20b%3D%5Cfrac%7B15%7D%7B5%7D%20%5C%5C%20b%3D3%20%5Cend%7Bgathered%7D)
We can interpret that either of a or b are equal to 3 or 5.
When a=3 and b=5, we have
![\begin{gathered} c=7(3)+2(5) \\ =21+10 \\ =31 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20c%3D7%283%29%2B2%285%29%20%5C%5C%20%3D21%2B10%20%5C%5C%20%3D31%20%5Cend%7Bgathered%7D)
When a=5 and b=3, we have
![\begin{gathered} c=7(5)+2(3) \\ =35+6 \\ =41 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20c%3D7%285%29%2B2%283%29%20%5C%5C%20%3D35%2B6%20%5C%5C%20%3D41%20%5Cend%7Bgathered%7D)
Final Answer:
The option D is correct.
31 and 41