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elixir [45]
4 years ago
6

WILL MARK THE FIRST CORRECT ANSWER BRAINLIEST!

Mathematics
2 answers:
ExtremeBDS [4]4 years ago
8 0

both angle 5 and 7 are °67

Darya [45]4 years ago
8 0

Answer:

63

Step-by-step explanation:

angle 5 is equal to angle 7 and angle 3 is equal to angle 5. Hence angle 5 is equal to 180-113=67    angle 3 and angle 4 is equal because they are supplementary meaning = 180 and we know angle 4 is equal to 113 so angle 3 is equal to 180-113 and angle 3 is equal to angle 5 because they are alternate interior angles. angle 5 and angle7 are vertically opposite angles so they are equal to each other so the asnwer is 63

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Find the area of the largest circle help me out i will have points ​
lilavasa [31]

Answer: 254.34 ^ 2

Step-by-step explanation:

To find the area of the circle use its formula

A = Pi * R^2                /  Area equals pie times radius squared

The two circles diameter combined is 18 meaning the radius is 9

So we plug 9 into the formula

A = 3.14 * 9^2

A = 3.14 * 81

A = 254.34 ^ 2

5 0
3 years ago
Helppp meeee pleaseeee
Alex_Xolod [135]

Answer:

y ≥ -2

Step-by-step explanation:

5y - 3 ≥ -13

   +3     +3

5y ≥ -10

5/5y ≥ -10/5

y ≥ -2

and since we didn't divide by any negative numbers the sign stays the same

6 0
3 years ago
How do I find this answer??
MArishka [77]
You do 2/3 minus 1/3

6 0
4 years ago
The band boosters collected $2400 from the sale of hamburgers and hotdogs.The amounts earned from hamburgers and hotdogs were eq
melomori [17]
(3x + 2x = 2400)
(5x = 2400)
(x = 480)
(480 were sold for each)
6 0
3 years ago
PLEASE HELP I HAVE AN HOUR LEFT!!
Yuki888 [10]

The statement that correctly describes the horizontal asymptote of g(x) is:

Limit of g (x) as x approaches plus-or-minus infinity = 6, so g(x) has an asymptote at y = 6.

<h3>What are the asymptotes of a function f(x)?</h3>

  • The vertical asymptotes are the values of x which are outside the domain, which in a fraction are the zeroes of the denominator.
  • The horizontal asymptote is the limit of f(x) as x goes to infinity, as long as this value is different of infinity.

In this problem, the function is:

g(x) = \frac{42x^3 - 15}{7x^3 - 4x^2 - 3}

The horizontal asymptote is given as follows:

y = \lim_{x \rightarrow \infty} g(x) = \lim_{x \rightarrow \infty} \frac{42x^3 - 15}{7x^3 - 4x^2 - 3} = \lim_{x \rightarrow \infty} \frac{42x^3}{7x^3} = \lim_{x \rightarrow \infty} 6 = 6

Hence the correct statement is:

Limit of g (x) as x approaches plus-or-minus infinity = 6, so g(x) has an asymptote at y = 6.

More can be learned about asymptotes at brainly.com/question/16948935

#SPJ1

5 0
2 years ago
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