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3 years ago

37/50 of a number is what percent of that number

Mathematics

2 answers:

GaryK [48]3 years ago

6 0

Using cross multiplication, multiply 37 by 100, then divide that by 50 and you get 74. 37/50 is 74%

nexus9112 [7]3 years ago

4 0

Answer:

The answer is 74%

Step-by-step explanation:

Method One:

1) Un-reduce the fraction to ger 74/100

2) Your answer is 74%

Method 2:

1) Divide 37 by 50

2) You get .74

3) Your answer is 74%

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What are two different ways you could find the value of a? Explain these methods.

tekilochka [14]

Step-by-step explanation:

What are two different ways you could find the value of a? Explain these methods. A right triangle is shown. An altitude is drawn from the right angle to the opposite side to form 2 line segments with lengths 9 and 16. The length of the other 2 sides are 15 and a....done

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2 years ago

Reggie ate 31 raisins. Which correctly describes 31 as a prime or a composite number and tells the number of factor pairs 31 has

kari74 [83]

Answer:

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Step-by-step explanation:

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3 years ago

the 11th term in a geometric sequence is 48 and the common ratio is 4. the 12th term is 192 and the 10th term is what?

Soloha48 [4]

Given:

The 11th term in a geometric sequence is 48.

The 12th term in the sequence is 192.

The common ratio is 4.

We need to determine the 10th term of the sequence.

General term:

The general term of the geometric sequence is given by

$a_n=a(r)^{n-1}$

where a is the first term and r is the common ratio.

The 11th term is given is

$a_{11}=a(4)^{11-1}$

$48=a(4)^{10}$ ------- (1)

The 12th term is given by

$192=a(4)^{11}$ ------- (2)

Value of a:

The value of a can be determined by solving any one of the two equations.

Hence, let us solve the equation (1) to determine the value of a.

Thus, we have;

$48=a(1048576)$

Dividing both sides by 1048576, we get;

$\frac{3}{65536}=a$

Thus, the value of a is $\frac{3}{65536}$

Value of the 10th term:

The 10th term of the sequence can be determined by substituting the values a and the common ratio r in the general term $a_n=a(r)^{n-1}$ , we get;

$a_{10}=\frac{3}{65536}(4)^{10-1}$

$a_{10}=\frac{3}{65536}(4)^{9}$

$a_{10}=\frac{3}{65536}(262144)$

$a_{10}=\frac{786432}{65536}$

$a_{10}=12$

Thus, the 10th term of the sequence is 12.

8 0

2 years ago

You have 100 yards of fencing available to create an enclosure for farm animals. As the

Sunny_sXe [5.5K]

1. area of a pentagon when 1 side is x is $\frac{x^2}{4}\sqrt{5(5+2\sqrt{5})}$
so if perimiter is 100 then one side is 100/5 or 20
area will be $\frac{20^2}{4}\sqrt{5(5+2\sqrt{5})}$ ≈688.2 square yards

2. area of a hexagon when 1 side is length x is $\frac{3x^2\sqrt{3}}{2}$
so if permiter is 100 then length of one side is 100/6 or about 16.666666666666
the area will be $\frac{3(16.6666666)^2\sqrt{3}}{2}$ ≈721.7 square yards

3. area of a regular octagon with side lenghts x is $2(1+\sqrt{2})x^2$
so if 8 sides then side length of each is 100/8 or 12.5
area will be $2(1+\sqrt{2})12.5^2$ ≈754.4 square yards

octagon wil have most space
you can tell because the more sides it has, the more it gets to a circle and the more area it encloses with a given perimiter

3 0

3 years ago

PLEASE HELP ASAP! I don’t recall how to do this!

MakcuM [25]

Answer:

Step-by-step explanation:

For a. we start by dividing both sides by 200:

$(1.05)^x=1.885$

In order to solve for x, we have to get it out from its position of an exponent. Do that by taking the natural log of both sides:

$ln(1.05)^x=ln(1.885)$

Applying the power rule for logs lets us now bring down the x in front of the ln:

x * ln(1.05) = ln(1.885)

Now we can divide both sides by ln(1.05) to solve for x:

$x=\frac{ln(1.885)}{ln(1.05)}$

Do this on your calculator to find that

x = 12.99294297

For b. we will first apply the rule for "undoing" the addition of logs by multipllying:

$ln(x*x^2)=5$

Simplifying gives you

$ln(x^3)=5$

Applying the power rule allows us to bring down the 3 in front of the ln:

3 * ln(x) = 5

Now we can divide both sides by 3 to get

$ln(x)=\frac{5}{3}$

Take the inverse ln by raising each side to e:

$e^{ln(x)}=e^{\frac{5}{3}}$

The "e" and the ln on the left undo each other, leaving you with just x; and raising e to the power or 5/3 gives you that

x = 5.29449005

For c. begin by dividing both sides by 20 to get:

$\frac{1}{2}=e^{.1x}$

"Undo" that e by taking the ln of both sides:

$ln(.5)=ln(e^{.1x})$

When the ln and the e undo each other on the right you're left with just .1x; on the left we have, from our calculators:

-.6931471806 = .1x

x = -6.931471806

Question d. is a bit more complicated than the others. Begin by turning the base of 4 into a base of 2 so they are "like" in a sense:

$(2^2)^x-6(2)^x=-8$

Now we will bring over the -8 by adding:

$(2^2)^x-6(2)^x+8=0$

We can turn this into a quadratic of sorts and factor it, but we have to use a u substitution. Let's let $u=2^x$

When we do that, we can rewrite the polynomial as

$u^2-6u+8=0$

This factors very nicely into u = 4 and u = 2

But don't forget the substitution that we made earlier to make this easy to factor. Now we have to put it back in:

$2^x=4,2^x=2$

For the first solution, we will change the base of 4 into a 2 again like we did in the beginning:

$2^2=2^x$

Now that the bases are the same, we can say that

x = 2

For the second solution, we will raise the 2 on the right to a power of 1 to get:

$2^x=2^1$

Now that the bases are the same, we can say that

x = 1

5 0

3 years ago