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Ne4ueva [31]
1 year ago
9

I need to know how to do this problem and graph it on a graph like this one below…Problem: Makayla earns $7 per hour at the bage

l shop and $12 per hour mowing lawns. Makayla needs to earn at least $120 per week, but must work less than 30 hours per week. Write and graph the system of linear inequalities that describes this situation. Graph:

Mathematics
1 answer:
kirza4 [7]1 year ago
3 0

Given that:

- Makayla earns $7 per hour at the bagel shop and $12 per hour mowing lawns.

- She needs to earn at least $120 per week, but must work less than 30 hours per week.

Let be "x" the number of hours Makayla works in the bagel shop, and "y" the number of hours she works in the mowing lawns.

Using the information given, you can set up the following System of Linear Inequalities:

\begin{cases}7x+12y\ge120 \\ x+y

The first inequality means that she needs to earn at least $120 per week, and the second inequality means that she needs to work less than 30 hours per week.

You can rewrite each equation by solving for "y":

- For the first inequality:

\begin{gathered} 12y\ge-7x+120 \\  \\ y\ge-\frac{7}{12}+\frac{120}{12} \\  \\ y\ge-\frac{7}{12}x+10 \end{gathered}

- And for the second inequality:

y

Notice that the boundary line of the first inequality is:

y=-\frac{7}{12}x+10

It is written in Slope-Intercept Form:

y=mx+b

Where "m" is the slope and "b" is the y-intercept.

Notice that, for the first line:

\begin{gathered} m_1=-\frac{7}{12} \\  \\ b_1=10 \end{gathered}

The slope indicates that the lines move 12 units to the right and 7 units down.

Since the symbol of the inequality is:

\ge

The line is solid and the shaded region is above the line.

The boundary line of the second inequality is:

y=-x+30

Notice that:

\begin{gathered} m_2=-1 \\ b_2=30 \end{gathered}

Since the symbol is "Less than", the line is dashed and the shaded region must be below the line.

Now you can graph the System of Linear Inequalities.

Hence, the answer is:

- System of Linear Inequalities:

\begin{cases}7x+12y\ge120 \\ x+y

- Graph:

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umka21 [38]
0.25% chance of getting at least three heads out of four coin flips.

8 0
3 years ago
Write out the equation: The difference of a number m and 30 is 10
inna [77]
M-30=10
It could also be 30-m=10
The answer for the first one would be 10+30=m
m=40
The answer for the second one would be 30-10=m
m=20

Hope this helps :)
4 0
4 years ago
Read 2 more answers
(−t 4 −5t 3 −10t 2 )+(9t 3 +3t 2 −1)
klemol [59]

Answer:

\left(-t^4-5t^3-10t^2\right)+\left(9t^3+3t^2-1\right)=-t^4+4t^3-7t^2-1

Step-by-step explanation:

Given the expression

\left(-t^4\:-5t^3\:-10t^2\:\right)+\left(9t^3\:+3t^2\:-1\right)

Remove parentheses:  (a)=a

=-t^4-5t^3-10t^2+9t^3+3t^2-1

Group like terms

=-t^4-5t^3+9t^3-10t^2+3t^2-1

Add similar elements        

=-t^4-5t^3+9t^3-7t^2-1         ∵ -10t^2+3t^2=-7t^2

Add similar elements        

=-t^4+4t^3-7t^2-1                  ∵  -5t^3+9t^3=4t^3

Thus, the equivalent expression in simplified form:

\left(-t^4-5t^3-10t^2\right)+\left(9t^3+3t^2-1\right)=-t^4+4t^3-7t^2-1

4 0
3 years ago
Steve likes to entertain friends at parties with "wire tricks." Suppose he takes a piece of wire 60 inches long and cuts it into
Alex_Xolod [135]

Answer:

a) the length of the wire for the circle = (\frac{60\pi }{\pi+4}) in

b)the length of the wire for the square = (\frac{240}{\pi+4}) in

c) the smallest possible area = 126.02 in² into two decimal places

Step-by-step explanation:

If one piece of wire for the square is y; and another piece of wire for circle is (60-y).

Then; we can say; let the side of the square be b

so 4(b)=y

         b=\frac{y}{4}

Area of the square which is L² can now be said to be;

A_S=(\frac{y}{4})^2 = \frac{y^2}{16}

On the otherhand; let the radius (r) of the  circle be;

2πr = 60-y

r = \frac{60-y}{2\pi }

Area of the circle which is πr² can now be;

A_C= \pi (\frac{60-y}{2\pi } )^2

     =( \frac{60-y}{4\pi } )^2

Total Area (A);

A = A_S+A_C

   = \frac{y^2}{16} +(\frac{60-y}{4\pi } )^2

For the smallest possible area; \frac{dA}{dy}=0

∴ \frac{2y}{16}+\frac{2(60-y)(-1)}{4\pi}=0

If we divide through with (2) and each entity move to the opposite side; we have:

\frac{y}{18}=\frac{(60-y)}{2\pi}

By cross multiplying; we have:

2πy = 480 - 8y

collect like terms

(2π + 8) y = 480

which can be reduced to (π + 4)y = 240 by dividing through with 2

y= \frac{240}{\pi+4}

∴ since y= \frac{240}{\pi+4}, we can determine for the length of the circle ;

60-y can now be;

= 60-\frac{240}{\pi+4}

= \frac{(\pi+4)*60-240}{\pi+40}

= \frac{60\pi+240-240}{\pi+4}

= (\frac{60\pi}{\pi+4})in

also, the length of wire for the square  (y) ; y= (\frac{240}{\pi+4})in

The smallest possible area (A) = \frac{1}{16} (\frac{240}{\pi+4})^2+(\frac{60\pi}{\pi+y})^2(\frac{1}{4\pi})

= 126.0223095 in²

≅ 126.02 in² ( to two decimal places)

4 0
4 years ago
−4p+9=−5<br><br> Help a sister out plz
Lorico [155]

Answer: p=7/2=3.5

Step-by-step explanation:

Given

-4p+9=-5

Subtract 9 on both sides

-4p+9-9=-5-9

-4p=-14

Divide -4 on both sides

-4p/-4=-14/-4

p=7/2=3.5

Hope this helps!! :)

Please let me know if you have any questions

4 0
3 years ago
Read 2 more answers
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