Any odd number can be expressed by 2n+1.
For example,
2n+1=111
2n=110
n=110/2=55
means that 111 is 2n+1 for n=55
Thus if an odd number is 2a+1, the next few numbers are as follows:
2a+1, 2a+2, 2a+3, 2a+4, 2a+5
So 2a+1, 2a+3 and 2a+5 are 3 consecutive odd numbers.
Back to our problem:
three consecutive odd numbers whose sum is 63 are:
(2n+1)+(2n+3)+(2n+5)=63
6n+9=63
6n=63-9=54
n=54/6=9
2n+1=2*9+1=18+1=19, the 2 next odd numbers are 21 and 23
Answer: 19, 21, 23
Answer:
Step-by-step explanation:
ok
Answer:
x=3/2, y=6
Step-by-step explanation:
plz mark brainliest!
Answer: 7:3
Step-by-step explanation:
15 chairs are red
35 are blue
35:15
Simplifies to
7:3
Answer:
x = 2
Step-by-step explanation:
To start, you want to isolate x.
To do so, get all the x terms to one side.
2x + 1 = 4x - 3
Subtract -4x on both sides.
-2x + 1 = -3
Then, subtract 1 on both sides.
-2x = -4
Finally, divide -2 on both sides.
x = 2