Suppose that m∠C = m∠F. Which other fact would guarantee that the triangles are SIMILAR
1 answer:
Properties of Similar Triangles
Please refer to the figure attached.
<span>Corresponding angles are congruent (same measure) So in the figure above, the angle P=P', Q=Q', and R=R'.
<span>
Corresponding sides are all in the same proportion. Above, PQ is twice the length of P'Q'. Therefore, the other pairs of sides are also in that proportion.</span></span>
Please refer to the figure attached.
<span>Corresponding angles are congruent (same measure) So in the figure above, the angle P=P', Q=Q', and R=R'.
<span>
Corresponding sides are all in the same proportion. Above, PQ is twice the length of P'Q'. Therefore, the other pairs of sides are also in that proportion.</span></span>
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Answer:
Follows are the solution to the given point:
Step-by-step explanation:
In point a:
¬∃y∃xP (x, y)
∀x∀y(>P(x,y))
In point b:
¬∀x∃yP (x, y)
∃x∀y ¬P(x,y)
In point c:
¬∃y(Q(y) ∧ ∀x¬R(x, y)) ∀y(> Q(y) V ∀ ¬ (¬R(x,y)))
∀y(¬Q(Y)) V ∃xR(x,y) )
In point d:
¬∃y(∃xR(x, y) ∨ ∀xS(x, y))
∀y(∀x>R(x,y)) ∃x>s(x,y))
In point e:
¬∃y(∀x∃zT (x, y, z) ∨ ∃x∀zU (x, y, z))
∀y(∃x ∀z)>T(x,y,z) ∀x ∃z> V (x,y,z))
Answer:
The height is 20 cm.
Step-by-step explanation:
First, we have to know that the volume formula is V = πr²h and the base area of cylinder is a circle. So we can let πr² be 77 cm² . Then we have to substitute the following values into the formula :
Let πr² be 77,
Let v be 1540,