What is the median of the data below?<br><br>
45, 19, 23, 67, 28, 35, 46, 21, 58, 60, 23, 51
VLD [36.1K]
To find the median, you will need to list the data from least to greatest and find the middle number.
19, 21, 23, 23, 28, 35, 45, 46, 51, 58, 60, 67
Cross out a number on both sides until you reach the middle number. In this case, we are left with 2 numbers that are in the middle since there is an even amount of numbers.
When you reach the time where you have two middle numbers, we have to find the average of those two numbers. Our two middle numbers are 35 and 45. Since we have to find the average of those two numbers, we can add them. (35 + 45 = 80). Now, since we have two middle numbers, we have to divide them by 2.

Answer:
The correct answer is 35.2 because when you arrange them in order from least to greatest, the middle is 35.2
Answer:
x=11.2
Step-by-step explanation:
Set up a proportion:
x+11/36 = 37/60
Cross multiply:
1332=60(x+11)
Distribute:
1332=60x+660
Subtract 660 from 1332
672=60x
Divide:
x=11.2
I'm not sure if this is the correct answer but I hope this helps! :)
Correct me if I'm wrong!
F(x) = 3x + 1
let f(x) = y
y = 3x + 1
y - 1 = 3x
3x = y - 1
x = (y - 1)/3
From y = f(x), x = f⁻¹(y)
<span>x = (y - 1)/3
</span>
f⁻¹(y) = (y - 1)/3
f⁻¹(7) = <span>(7 - 1)/3 = 6/3 = 2
</span>f⁻¹(7)<span> = 2</span>