All categories

3 years ago

2.) What is the mean number of boys in the three classes? What is the mean number of girls in the three classes?

Mathematics

2 answers:

SCORPION-xisa [38]3 years ago

4 0

Answer:

2.) Mean for boys: 13

Mean for girls: 14

3) No mode

4) 14

Step-by-step explanation:

2.) Finding mean for boys: 15+12+12 = 39

39/3 = 13

Finding mean for girls: 14+12+16 = 42

42/3 = 14

4.) 12, 14, 16

Median: 14 (middle number when put in ascending order)

Luden [163]3 years ago

3 0

1.for boys is 13 and for girls it is 14 2. no mode 3. 13.5

You might be interested in

The speed of one type of bullet is 200 meters per second. How long would it take the bullet to travel 5,000 meters?

bekas [8.4K]

To solve this problem, we have to find how long it will take the bullet to travel 5,000 meters. We know that it travels 200 meters per second.

Therefore, if you divide 5,000 meters/200 meters per second, it will give you how many seconds it will take the bullet to travel 5,000 meters.

5,000/200 = 25

Therefore, it will take 25 seconds for the bullet to travel 5,000 meters.

8 0

3 years ago

PLEASE HELP!!!<br> Find MG.<br> ∆EGF~∆EML.

stiv31 [10]

Answer:

$MG=56\ units$

Step-by-step explanation:

step 1

Find the value of x

we know that

If two triangles are similar, then the ratio of its corresponding sides is proportional and its corresponding angles are congruent

In this problem we have that

∆EGF~∆EML

$\frac{EG}{EM}=\frac{EF}{EL}$

substitute the given values

$\frac{5x+2}{16}=\frac{126}{28}$

solve for x

$5x+2=\frac{126}{28}(16)$

$5x+2=72\\5x=70\\x=14$

$EG=5x+2=5(14)+2=72\ units$

step 2

Find MG

we know that

$MG=EG-EM$

substitute

$MG=72-16=56\ units$

3 0

3 years ago

Every morning Jenna runs for 20 min . If Jenna runs 6 miles per hour , how far does she travel

DerKrebs [107]

20 minutes* (1 hour/ 60 minutes)* (6 miles/ 1 hour)= 2 miles.
(Note that the units cancel out so you end up getting the answer)

The final answer is 2 miles~

6 0

3 years ago

18. What's 7?8 as a decimal? A. .78 B. 8.7 C. .875 D. 7.8

kenny6666 [7]

Each 1/8 is 0.125, so 7*0.125 in relation to 7/8 as a decimal is 0.875. Answer C.

3 0

3 years ago

Birth weights of babies born to full-term pregnancies follow roughly a Normal distribution. At Meadowbrook Hospital, the mean we

Marina86 [1]

Answer:

Required Probability = 0.1283 .

Step-by-step explanation:

We are given that at Meadow brook Hospital, the mean weight of babies born to full-term pregnancies is 7 lbs with a standard deviation of 14 oz.

Firstly, standard deviation in lbs = 14 ÷ 16 = 0.875 lbs.

Also, Birth weights of babies born to full-term pregnancies follow roughly a Normal distribution.

Let X = mean weight of the babies, so X ~ N( $\mu = 7 lbs , \sigma^{2} = 0.875^{2} lbs$ )

The standard normal z distribution is given by;

Z = $\frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, X bar = sample mean weight

n = sample size = 4

Now, probability that the average weight of the four babies will be more than 7.5 lbs = P(X bar > 7.5 lbs)

P(X bar > 7.5) = P( $\frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } }$ > $\frac{7.5-7}{\frac{0.875}{\sqrt{4} } }$ ) = P(Z > 1.1428) = 0.1283 (using z% table)

Therefore, the probability that the average weight of the four babies will be more than 7.5 lbs is 0.1283 .

8 0

3 years ago