Answer:
83! :)
Step-by-step explanation:
It all equals 180.
So,
53+44+?=180
180-53-44=83! :)
83+53+44=180! :)
1.)
Between year 0 and year 1, we went from $50 to $55.
$55/$50 = 1.1
The price increased by 10% from year 0 to year 1.
Between year 2 and year 1, we went from $55 to $60.50.
$60.50/$55 = 1.1
The price also increased by 10% from year 1 to year 2. If we investigate this for each year, we will see that the price increases consistently by 10% every year.
The sequence can be written as an = 50·(1.1)ⁿ
2.) To determine the price in year 6, we can use the sequence formula we established already.
a6 = 50·(1.1)⁶ = $88.58
The price of the tickets in year 6 will be $88.58.
An = a1 + (n-1) * d
a12 = 47 + (12 - 1) * -5
a12 = 47 + 11 * -5
a12 = 47 - 55
a12 = - 8 <==
No star is higher; they're the same.
y = 10x + 30
Substitute "9x + 40" with y.
Then you get 9x + 40 = 10x + 30.
Get the variables on one side and the numbers on one side.
Basic algebra used here subtract 9x from both sides. Then subtract 30 from both sides and you will get x = 10.
Plug 10 for X into the equation and you will get Y = 130. Try each problem separately and you will get the same answer for both so they're equal, none is higher.
Answer:
10
Step-by-step explanation:
2+5 = 7
35/7 = 5
2 × 5 = 10
hope this helps...
