Let s = side length of square, then
200=s^2, or
s=sqrt(200)=sqrt(2*10^2)=10sqrt(2)
The diagonal turns out to be sqrt(s^2+s^2) by the Pythagoras theorem and equals sqrt(2s^2)=s*sqrt(2) = 10sqrt(2)*sqrt(2)=10*2=20.
In general, the diagonal D of a square with area A is given by
D=sqrt(2)*sqrt(A)=sqrt(2A)
In the case given it is Diagonal length = sqrt(2*200)=sqrt(400)=20 (as before)
Answer:
I'm pretty sure the answer is still 6x-5.
Step-by-step explanation:
5r + 6s = 53
25r + 3s = 49
Meaning of simultaneous is to solve by elimination
Multiply the equation 2 by -2
-2( 25r + 3s = 49)
-50r – 6s = -98
Then add the two equation to eliminate s, so the resulting equation is:
-45r =-45
r = 1
substitute r = 1 to equation 1
5(1) + 6s = 53
6s = 53 – 5
6s = 48
<span>S = 8</span>
16 or more books sold in a day will include two intervals from the given table:
a) 16 - 20 books sold.
Probability = 0.201
b) 21 - 25 books sold.
Probability = ?
Since the table gives the probability distribution, the sum of all the probabilities must be equal to 1. We are given the probabilities of 4 out 5 intervals. So in order to find the probability of the 5th interval (21-25) we can subtract the sum of probabilities of rest of the intervals from 1.
So, P(21 - 25) = 0.019
In order to find the probability of 16 or more books sold we need to sum the probabilities of both these intervals.
So, the probability of 16 or more books being sold on a given day = 0.201 + 0.019 = 0.220
