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olga_2 [115]
3 years ago
8

Please help me I really need help

Mathematics
2 answers:
QveST [7]3 years ago
5 0

Answer:

83/10 ; 9.01 ; 97/10 ; 9.87

Step-by-step explanation:

Simplify the fractions, and then you can easily see the answer.

Ivenika [448]3 years ago
4 0

Answer: 83/10, 9.01, 97/10, 9.87

Step-by-step explanation:

We can choose to either write all the numbers indecimals or fractions. Let's choose decimals.

83/10=8.30

97/10=9.70

9.87

9.01

Now that we know the decimals, we can put them in order.

8.30, 9.01, 9.70, 9.87

Though this is correct, it is not the answer we are looking for. When we were given the problem, we had fractions. We must change the decimals back into fractions.

83/10, 9.01, 97/10, 9.87

This is our correct answer.

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Step-by-step explanation:

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3 years ago
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Answer:

Step-by-step explanation:

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2x+2=6 2x+2-2=6-2 \ \ \ substract \ \ 2\\ 2x = 4  \dfrac{2x}{2}=x=\dfrac{4}{2}=2 \ \ \ divide \ \ by  \ \ 2\\

so the solution is 2

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3 0
4 years ago
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A statistics teacher started class one day by drawing the names of 10 students out of a hat and asked them to do as many pushups
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Using the t-distribution, we have that the 95% confidence interval for the true mean number of pushups that can be done is (9, 21).

For this problem, we have the <u>standard deviation for the sample</u>, thus, the t-distribution is used.

  • The sample mean is of 15, thus \overline{x} = 15.
  • The sample standard deviation is of 9, thus s = 9.
  • The sample size is of 10, thus n = 10.

First, we find the number of degrees of freedom, which is the one less than the sample size, thus df = 9.

Then, looking at the t-table or using a calculator, we find the critical value for a 95% confidence interval, with 9 df, thus t = 2.2622.

The margin of error is of:

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The confidence interval is (9, 21).

A similar problem is given at brainly.com/question/25157574

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4(10+16)

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