Answer: a
Step-by-step explanation:
Answer:
Maggie's answer is going to be approximately 2 miles.
Step-by-step explanation:
2. 
Domain:
, because any value of
is allowed and gives a number
.
Range:
, because
for any positive real
.
y-intercept: This is a point of the form
. So plug in
; we get
. So the intercept is (0, 2), or just 2. (Interestingly, you didn't get marked wrong for that...)
Asymptote: This can be deduced from the range; the asymptote is the line
.
Increasing interval: Going from left to right, there is no interval on which
is increasing, since 1/4 is between 0 and 1.
Decreasing interval: Same as the domain;
is decreasing over the entire real line.
End behavior: The range tells you
, and you know
is decreasing over its entire domain. This means that
as
, and
and
.
3. 
Domain: Same as (2),
.
Range: We can rewrite
.
for all
, so
for all
. Then the range is
.
y-intercept: We have
, so the intercept is (0, -6) (or just -6).
Asymptote: 
Increasing interval: Not increasing anywhere
Decreasing interval: 
End behavior: Similar to (2), but this time
as
and
as
.
Answer:
2
Step-by-step explanation:
You would use PEMDAS( parentheses exponents multiply adding subtracting) (1/2)4.
^
o.5×4
^
2
Answer:
See explanation
Step-by-step explanation:
The given expression is: 
Recall that 24=3*8

Recall again that:





We rewrite in radical form to obtain
![\implies (8*3)^{\frac{1}{3}}=2\sqrt[3]{3}](https://tex.z-dn.net/?f=%5Cimplies%20%288%2A3%29%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D%3D2%5Csqrt%5B3%5D%7B3%7D)