Answer:
True
Step-by-step explanation:
6x² - 4y - 3x + 6x² + 8x = 12x² + 5x - 4y
Regroup terms on left
6x² + 6x² - 3x + 8x - 4y = 12x² + 5x - 4y
Combine like terms
on left
12x² + 5x - 4y = 12x² + 5x - 4y True
Answer:
4x - 12
Step-by-step explanation:
8-4(-x+5)
Distribute
8 - 4*-x -4 * 5
8 +4x - 20
Combine like terms
4x - 12
it is easy 90x+90y then divide by 4
Step-by-step explanation:
The two numbers are 30 and 11
<em><u>Solution:</u></em>
Given that we have to separate the number 41 into two parts
Let the second number be "x"
<em><u>Given that first number is eight more than twice the second number</u></em>
first number = eight more than twice the second number
first number = 8 + twice the "x"
first number = 8 + 2x
So we can say first number added with second number ends up in 41
first number + second number = 41
8 + 2x + x = 41
8 + 3x = 41
3x = 41 - 8
3x = 33
x = 11
first number = 8 + 2x = 8 + 2(11) = 8 + 22 = 30
Thus the two numbers are 30 and 11
