1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
noname [10]
3 years ago
15

At 1:00 p.m. u have 24 megabytes of a movie. At 1:15 p.m. u have 96 megabytes. What is the downloads rate in megabytes per minut

e?
Mathematics
1 answer:
guajiro [1.7K]3 years ago
5 0

Answer:

I believe it is 4.8

Step-by-step explanation:

96-24= 72

72/15 minutes= 4.8

You might be interested in
It cost Alexandra $9.90 to send 198 text messages. How many text messages did she send if she spent $2.35?
tatiyna

Answer:

77

Step-by-step explanation:

4 0
4 years ago
Read 2 more answers
For each value of u, determine whether it is a solution to -15 = 1 - 4u
Alona [7]

Answer:

1. No

2. No

3. No

4. Yes

Step-by-step explanation:

Plug each option into u then solve the equation and see if the answer matches -15.

Ex. -15 = 1 -4 (2)

     -15 = 1 -8

     -15 = -7

     -15 does not equal -7 therefore it is false. Use Pemdas to solve.

6 0
3 years ago
Given the sequence 1/2 ; 4 ; 1/4 ; 7 ; 1/8 ; 10;.. calculate the sum of 50 terms
miv72 [106K]

<u>Hint </u><u>:</u><u>-</u>

  • Break the given sequence into two parts .
  • Notice the terms at gap of one term beginning from the first term .They are like \dfrac{1}{2},\dfrac{1}{4},\dfrac{1}{8} . Next term is obtained by multiplying half to the previous term .
  • Notice the terms beginning from 2nd term , 4,7,10,13 . Next term is obtained by adding 3 to the previous term .

<u>Solution</u><u> </u><u>:</u><u>-</u><u> </u>

We need to find out the sum of 50 terms of the given sequence . After splitting the given sequence ,

\implies S_1 = \dfrac{1}{2},\dfrac{1}{4},\dfrac{1}{8} .

We can see that this is in <u>Geometric</u><u> </u><u>Progression </u> where 1/2 is the common ratio . Calculating the sum of 25 terms , we have ,

\implies S_1 = a\dfrac{1-r^n}{1-r} \\\\\implies S_1 = \dfrac{1}{2}\left[ \dfrac{1-\bigg(\dfrac{1}{2}\bigg)^{25}}{1-\dfrac{1}{2}}\right]

Notice the term \dfrac{1}{2^{25}} will be too small , so we can neglect it and take its approximation as 0 .

\implies S_1\approx \cancel{ \dfrac{1}{2} } \left[ \dfrac{1-0}{\cancel{\dfrac{1}{2} }}\right]

\\\implies \boxed{ S_1 \approx 1 }

\rule{200}2

Now the second sequence is in Arithmetic Progression , with common difference = 3 .

\implies S_2=\dfrac{n}{2}[2a + (n-1)d]

Substitute ,

\implies S_2=\dfrac{25}{2}[2(4) + (25-1)3] =\boxed{ 908}

Hence sum = 908 + 1 = 909

7 0
3 years ago
Tim is paid $100 per day and $25 per hour for over time. He did over time of 3 hours for 2 days and 4 hours for 3 days in a week
telo118 [61]

Answer:

$1125

Step-by-step explanation:

100d + 25h = $$

100(3) + 100(3) + 25(3*3) + 25(3*4) =

300 + 300 + 225 + 300 =

1125

6 0
3 years ago
Lower bound is 18, upper bound is 28. what is the point estimate of the population mean
hichkok12 [17]
23 is the mean estimate
7 0
4 years ago
Read 2 more answers
Other questions:
  • I REALLY NEED HELP
    9·1 answer
  • Due to the increase of posts on social media, the number of flip cell phones is in exponential decline. Data collected from 2009
    5·1 answer
  • Stanley Bank offers a money market account that earns 1.85% compounded continuously: a) If $10,000 is invested in this type of a
    8·1 answer
  • Identify the correct measure of the Thumbtack to the nearest 1/8 inch ​
    7·1 answer
  • What number is 5 10's greater than 89?
    9·1 answer
  • Need help for this question asap please
    13·1 answer
  • MAY GIVE BRAINLIEST!
    12·2 answers
  • How many real and how many are imaginary<br> Please Explain how to do it
    14·2 answers
  • Which value must be added to the expression x2 + 12x to make it a perfect-square trinomial?
    6·1 answer
  • Perry bought 5 nectarines for $4. how many nectarines can amanda buy if she has 16$
    5·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!