All categories

3 years ago

Plz help me thank you

Mathematics

1 answer:

d1i1m1o1n [39]3 years ago

5 0

Answer:

I think and sorry if I am wrong but it is 780 ounces

You might be interested in

The first term of a sequence is 35 and the difference between the terms is always 8. a) Determine the nth term of the sequence.

s2008m [1.1K]

Answer:

Step-by-step explanation:

$a_1=35\\d=8\\\\a_n=a_1+d(n-1)\\\\a_n=35+8(n-1)\\a_n=35+8n-8\\a_n=8n+27$

8 0

3 years ago

I have to get this done bc its the last day of school fm. So please help me :)))

kobusy [5.1K]

Answer: it is the median

Step-by-step explanation:

5 0

1 year ago

Read 2 more answers

What is the equation of the line that passes through the points (-3,5) (6,8)

Ratling [72]

$(\stackrel{x_1}{-3}~,~\stackrel{y_1}{5})\qquad (\stackrel{x_2}{6}~,~\stackrel{y_2}{8}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{8}-\stackrel{y1}{5}}}{\underset{run} {\underset{x_2}{6}-\underset{x_1}{(-3)}}}\implies \cfrac{3}{6+3}\implies \cfrac{3}{9}\implies \cfrac{1}{3}$

$\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{5}=\stackrel{m}{\cfrac{1}{3}}(x-\stackrel{x_1}{(-3)}) \\\\\\ y-5=\cfrac{1}{3}(x+3)\implies y-5=\cfrac{1}{3}x+1\implies y=\cfrac{1}{3}x+6$

6 0

2 years ago

In an effort to estimate the mean of amount spent per customer for dinner at a major Lawrence restaurant, data were collected fo

larisa86 [58]

Answer:

The 99% confidence interval for the population mean is 22.96 to 26.64

Step-by-step explanation:

Consider the provided information,

A sample of 49 customers. Assume a population standard deviation of $5. If the sample mean is $24.80,

The confidence interval if 99%.

Thus, 1-α=0.99

α=0.01

Now we need to determine $z_{\frac{\alpha}{2}}=z_{0.005}$

Now by using z score table we find that $z_{\frac{\alpha}{2}}=2.58$

The boundaries of the confidence interval are:

$\mu-z_{\frac{\alpha}{2}}\times \frac{\sigma}{\sqrt{n} }\\24.80-2.58\times \frac{5}{\sqrt{49}}=22.96\\\mu+z_{\frac{\alpha}{2}}\times \frac{\sigma}{\sqrt{n} }\\24.80+2.58\times \frac{5}{\sqrt{49}}=26.64$

Hence, the 99% confidence interval for the population mean is 22.96 to 26.64

3 0

3 years ago

A scientist raised $32,506 for his project. He later found out that he would need $57,500 to completely pay for it. How much mor

hammer [34]

We need to subtract: the scientist needed 57,500 dollars, but already had 32,506, so we need to find what's left: 57,500 - 32,506 = 24,992 dollars

Your answer is A. Hope that helps! :)

3 0

3 years ago

Read 2 more answers