Answer:
The Annual rate of interest for the mortgage is 1.8%
Step-by-step explanation:
Given as :
The mortgage principal = p = $167,000
The time period of mortgage = t = 20 years
The Amount paid towards mortgage in 20 years = A = $240,141
Let the Annual percentage rate on interest = r % compounded annually
Now, <u>From Compound Interest method</u>
Amount = Principal × 
Or, A = p × 
Or, $240,141 = $167,000 × 
or, 
=
Or , 1.437 =
Or, 
= 
or, 1.018 =
Or, 
= 1.018 - 1
Or, = 0.018
∴ r = 0.018 × 100
i.e r = 1.8
So, The rate of interest applied = r = 1.8 %
Hence, The Annual rate of interest for the mortgage is 1.8% Answer
Answer:
The location of the point is between Quadrant II and Quadrant III
Step-by-step explanation:
we know that
The abscissa refers to the x-axis and ordinate refers to the y-axis
so
in this problem we have
the coordinates of the point are 
see the attached figure to better understand the problem
The location of the point is between Quadrant II and Quadrant III
Answer:
a) $3480
b) $4036.8
Step-by-step explanation:
The compound interest formula is given by:
Where A(t) is the amount of money after t years, P is the principal(the initial sum of money), r is the interest rate(as a decimal value), n is the number of times that interest is compounded per year and t is the time in years for which the money is invested or borrowed.
Suppose that $3000 is placed in an account that pays 16% interest compounded each year.
This means, respectively, that 
So
(a) Find the amount in the account at the end of 1 year.
This is A(1).
(b) Find the amount in the account at the end of 2 years.
This is A(2).
Answer:
D
Step-by-step explanation:
![f(x)=(x-1)(x^2+2)^3\\f'(x)=(x-1)*3(x^2+2)^2*2x+(x^2+2)^3*1\\f'(x)=6x(x-1)(x^2+2)^2+(x^2+2)^3\\f'(x)=(x^2+2)^2[6x^2-6x+x^2+2]\\f'(x)=(x^2+2)^2(7x^2-6x+2)\\D](https://tex.z-dn.net/?f=f%28x%29%3D%28x-1%29%28x%5E2%2B2%29%5E3%5C%5Cf%27%28x%29%3D%28x-1%29%2A3%28x%5E2%2B2%29%5E2%2A2x%2B%28x%5E2%2B2%29%5E3%2A1%5C%5Cf%27%28x%29%3D6x%28x-1%29%28x%5E2%2B2%29%5E2%2B%28x%5E2%2B2%29%5E3%5C%5Cf%27%28x%29%3D%28x%5E2%2B2%29%5E2%5B6x%5E2-6x%2Bx%5E2%2B2%5D%5C%5Cf%27%28x%29%3D%28x%5E2%2B2%29%5E2%287x%5E2-6x%2B2%29%5C%5CD)
Answer:
The approximate temperature of the pan after it has been away from the heat for 9 minutes is 275.59°F.
Step-by-step explanation:
The formula for D, the difference in temperature between the pan and the room after t minutes is:
Compute the approximate difference in temperature between the pan and the room after 9 minutes as follows:
Then the approximate temperature of the pan after it has been away from the heat for 9 minutes is:
D = P - R
206.59 = P - 69
P = 206.59 + 69
P = 275.59°F
Thus, the approximate temperature of the pan after it has been away from the heat for 9 minutes is 275.59°F.
