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Kazeer [188]
3 years ago
14

I need to rent a car for my forthcoming trip. Rent-N-Go charges $21 per day plus 15 cents per mile. Super Rentals Plus charges $

18.50 per day plus 21 cents per mile.I plan to do a good deal of driving during all three days of my trip, and I need to know which company will give me a better deal overall. How many miles would I have to drive to make the cost of renting a car from Rent-N-Go the same as the cost of renting a car from Super Rentals Plus? Explain how I should decide which rental car company to use.
Mathematics
1 answer:
Nastasia [14]3 years ago
6 0

Answer:

ummmmm its umm 2 duhhhhhhhhhhhhhhh

Step-by-step explanation:

i think

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The Cunninghams are moving across the country. Mr. Cunningham leaves 3 hours before Mrs. Cunningham. If he averages 40mph and sh
svp [43]
Recall your d = rt, distance = rate * time

now, if say, by the time they meet, Mr Cunningham has travelled "d" miles, that means Mrs Cunningham must also had travelled "d" miles as well.

However, he left 3 hours earlier, so by the time he travelled "d" miles, and took say "t" hours, for her it took 3 hour less, because she started driving 3 hours later, so, she's been on the road 3 hours less than Mr Cunningham, so by the time they meet, Mrs Cunningham has travelled then "t - 3" hours.

\bf \begin{array}{lccclll}
&\stackrel{miles}{distance}&\stackrel{mph}{rate}&\stackrel{hours}{time}\\
&------&------&------\\
\textit{Mr Cunningham}&d&40&t\\
\textit{Mrs Cunningham}&d&80&t-3
\end{array}
\\\\\\
\begin{cases}
\boxed{d}=40t\\
d=80(t-3)\\
----------\\
\boxed{40t}=80(t-3)
\end{cases}
\\\\\\
\cfrac{40t}{80}=t-3\implies \cfrac{t}{2}=t-3\implies t=2t-6\implies 6=2t-t
\\\\\\
6=t
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Answer:

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2 years ago
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