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2 years ago

Which experimental design compares two groups (randomly formed) on the same task, such as movement speed

Mathematics

1 answer:

anygoal [31]2 years ago

3 0

Between-group design compares two groups (randomly formed) on the same task, such as movement speed.

Given things that there are two groups that are randomly formed for the same task.

A between-group design in experimental design is an experiment in which two or more groups of individuals are assessed simultaneously by separate testing factors. This design is typically used instead of, or in conjunction with, the within-subject design, which applies identical modifications of circumstances to each participant in order to monitor the reactions.

Learn more about experimental designs at brainly.com/question/17280313

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Express as a fraction in the simplest form: 43.5%

frez [133]

Answer:

Step-by-step explanation:

43.5 x 10 = 435

435/1000 = 87/200 (simplified)

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2 years ago

Subtract. Write your answer as a mixed number in simplest form.<br><br> 8 1/4 + 4 5/6

Tasya [4]

Answer:

13 1/12

Step-by-step explanation:

6 0

3 years ago

5-2 ????=7-5 ???? which value of x is the solution to the above equation?

saw5 [17]

5-2x=7-5x
-2x+5x=7-5
3x=2
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4 years ago

In class A, John got 85 for his first test John's class mean was 75 and standard deviation was 5. In class B, Kathy got 80 in he

ivanzaharov [21]

Answer:

b. Kathy

Step-by-step explanation:

We compare each of their score by how far away from the mean when in term of the standard deviation. Using the following formula

$\frac{x - \mu}{\sigma}$

For John he is (85 - 75)/5 = 2.

For Kathy she is (80 - 50)/10 = 3.

Since Kathy is 3 standard deviation better than her class' average, while John is only 2's. We conclude that Kathy did better.

6 0

3 years ago

which of the following gives an equation of a line that passes through the point (6 over 5, -19 over 5) and is parallel to the l

victus00 [196]

One equation for this would be

$y = \frac{41}{16} x-\frac{55}{8}$

We start by finding the slope between the two points:

$m=\frac{y_2-y_1}{x_2-x_1}=\frac{-12-\frac{-19}{5}}{-2-\frac{6}{5}}
\\
\\=(-12+\frac{19}{5}) \div (-2-\frac{6}{5})
\\
\\=(\frac{-60}{5}+\frac{19}{5}) \div (\frac{-10}{5}-\frac{6}{5})
\\
\\=\frac{-41}{5} \div \frac{-16}{5}=\frac{-41}{5} \times \frac{-5}{16}=\frac{41}{16}$

A line parallel to this one will have the same slope. We will use point-slope form to write our equation:

$y-y_1=m(x-x_1)
\\
\\y-\frac{-19}{5}=\frac{41}{16}(x-\frac{6}{5})
\\
\\y+\frac{19}{5}=\frac{41}{16}x- \frac{41}{16} \times \frac{6}{5}
\\
\\y+\frac{19}{5}=\frac{41}{16}x-\frac{246}{80}
\\
\\y+\frac{304}{80}=\frac{41}{16}x-\frac{246}{80}
\\
\\y=\frac{41}{16}x-\frac{246}{80}-\frac{304}{80}
\\
\\y=\frac{41}{16}x-\frac{550}{80}
\\
\\y=\frac{41}{16}x-\frac{55}{8}$

6 0

3 years ago