Ask question

Ask question

All categories

1 year ago

7

Which experimental design compares two groups (randomly formed) on the same task, such as movement speed

1 answer:

anygoal [31]1 year ago

3 0

Between-group design compares two groups (randomly formed) on the same task, such as movement speed.

Given things that there are two groups that are randomly formed for the same task.

A between-group design in experimental design is an experiment in which two or more groups of individuals are assessed simultaneously by separate testing factors. This design is typically used instead of, or in conjunction with, the within-subject design, which applies identical modifications of circumstances to each participant in order to monitor the reactions.

Learn more about experimental designs at brainly.com/question/17280313

#SPJ4

You might be interested in

Evaluate 2x-4y for x = 2 and y = 4.

tamaranim1 [39]

<em>Evaluate 2x-4y for x=2 and y=4.</em>
Replace x with 2 and y with 4.
2(2)-4(4)
Simplify.
4-16
-12

3 0

3 years ago

Read 2 more answers

Write an equation of the line that passes through (1,2) and is parallel to the line y = -5x +4

STatiana [176]

Answer:

y=-5x+7

Step-by-step explanation:

Prallel lines have the same slope

so the slope of the unknown line is -5

and passes through(1,2)

y-2=-5(x-1)

slope-intercept form:y=-5x+7

6 0

3 years ago

Help me PLZZZZ ITSS EASSYYYYYY

vodka [1.7K]

Answer:

The total cost y of a meal.....

Step-by-step explanation:

The total cost of the meal Y suggests addition, which if you added the x and w portions, you would end up with y.

The other answers suggest subtraction, division, or multiplication, which is not being illustrated by the model.

5 0

3 years ago

PLEASE HELP ME GEOMETRY

Aloiza [94]

Answer is B. second choice

Segments DE and AC are parallel by construction

4 0

3 years ago

Help answer and EXPLAIN STEP BY STEP

pychu [463]

15. $(-k^{3} -5k^{2} + 1) - (6k^{3}-k^{2} -2)$

Step 1: Distribute the subtraction sign to all the numbers in the second set of parentheses...

$(-k^{3} -5k^{2} + 1) - (6k^{3}-k^{2} -2)$

$-k^{3} -5k^{2} +1 - 6k^{3} +k^{2} +2$

Step 2: Combine like terms ( $k^{2}$ 's go with $k^{2}$ 's)

$-k^{3} -5k^{2} + 1 - 6k^{3}+k^{2} +2$

$-5k^{2} +k^{2}$

$-4k^{2}$

$-k^{3} -4k^{2} + 1 - 6k^{3}+2$

Step 3: Combine like terms ( $k^{3}$ 's go with $k^{3}$ 's)

$-k^{3} -4k^{2} + 1 - 6k^{3}+2$

$-k^{3} + (- 6k^{3})$

$-7k^{3}$

$-7k^{3} -4k^{2} + 1 +2$

Step 4: Combine like terms (normal numbers go with normal numbers)

$-7k^{3} -4k^{2} + 1 +2$

1 + 2

3

$-7k^{3} -4k^{2} + 3$

You were correct!

16. $49m^2 - 84mn + 36n^2$

I don't really know how to explain this one but I got: (7m-6n)(7m-6n)

7 0

3 years ago