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soldi70 [24.7K]
3 years ago
6

Write the absolute value inequality for the following: Do not solve.

Mathematics
2 answers:
Naddik [55]3 years ago
7 0

Answer:

  |s -55| ≤ 3

Step-by-step explanation:

"Within 3 mph of 55 mph" means the magnitude of the difference between s and 55 is at most 3. In symbols, this is ...

  |s -55| ≤ 3

JulijaS [17]3 years ago
4 0

Answer:

|s -55| ≤ 3

Step-by-step explanation:

The cruise control of a car set a 55mph should keep the speed (s) within 3 mph of 55mph.

The absolute value inequality for the given statement, without solving is

|s -55| ≤ 3/

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(x - 2)(x + 1) = 3x - 2
ratelena [41]

Answer:

x=4

Step-by-step explanation:

(x-2)(x+1)=3x-2

x(x+1)-2(x+1)=3x-2

x^2+x-2x-2=3x-2

x^2-x-2=3x-2

x^2=3x+x-2+2

x^2=4x

x^2/x=4

x=4

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Evaluate each algebraic expression for given value of the variable
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Help me please Help me ​
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Solve the following and explain your steps. Leave your answer in base-exponent form. (3^-2*4^-5*5^0)^-3*(4^-4/3^3)*3^3 please st
Naily [24]

Answer:

\boxed{2^{\frac{802}{27}} \cdot 3^9}

Step-by-step explanation:

<u>I will try to give as many details as possible. </u>

First of all, I just would like to say:

\text{Use } \LaTeX !

Texting in Latex is much more clear and depending on the question, just writing down without it may be confusing or ambiguous. Be together with Latex! (*^U^)人(≧V≦*)/

$(3^{-2} \cdot 4^{-5} \cdot 5^0)^{-3} \cdot (4^{-\frac{4}{3^3} })\cdot 3^3$

Note that

\boxed{a^{-b} = \dfrac{1}{a^b}, a\neq 0 }

The denominator can't be 0 because it would be undefined.

So, we can solve the expression inside both parentheses.

\left(\dfrac{1}{3^2}  \cdot \dfrac{1}{4^5}  \cdot 5^0 \right)^{-3} \cdot \left(\dfrac{1}{4^{\frac{4}{3^3} } }\right)\cdot 3^3

Also,

\boxed{a^{0} = 1, a\neq 0 }

\left(\dfrac{1}{9}  \cdot \dfrac{1}{1024}  \cdot 1 \right)^{-3} \cdot \left(\dfrac{1}{4^{\frac{4}{27} } }\right)\cdot 27

Note

\boxed{\dfrac{1}{a} \cdot \dfrac{1}{b}= \frac{1}{ab} , a, b \neq  0}

\left(\dfrac{1}{9216}   \right)^{-3} \cdot \left(\dfrac{1}{4^{\frac{4}{27} } }\right)\cdot 27

\left(\dfrac{1}{9216}   \right)^{-3} \cdot \left(\dfrac{27}{4^{\frac{4}{27} } }\right)

\left( \dfrac{1}{\left(\dfrac{1}{9216}\right)^3} \right)\cdot \left(\dfrac{27}{4^{\frac{4}{9} } }\right)

\left( \dfrac{1}{\left(\dfrac{1}{9216}\right)^3} \right)\cdot \left(\dfrac{27}{4^{\frac{4}{27} } }\right)

Note

\boxed{\dfrac{1}{\dfrac{1}{a} }  = a}

9216^3\cdot \left(\dfrac{27}{4^{\frac{4}{9} } }\right)

\left(\dfrac{ 9216^3\cdot 27}{4^{\frac{4}{27} } }\right)

Once

9216=2^{10}\cdot 3^2 \implies  9216^3=2^{30}\cdot 3^6

\boxed{(a \cdot b)^n=a^n \cdot b^n}

And

$4^{\frac{4}{27}} = 2^{\frac{8}{27} $

We have

\left(\dfrac{ 2^{30} \cdot 3^6\cdot 27}{2^{\frac{8}{27} } }\right)

Also, once

\boxed{\dfrac{c^a}{c^b}=c^{a-b}}

2^{30-\frac{8}{27}} \cdot 3^6\cdot 27

As

30-\dfrac{8}{27} = \dfrac{30 \cdot 27}{27}-\dfrac{8}{27}  =\dfrac{802}{27}

2^{30-\frac{8}{27}} \cdot 3^6\cdot 27 = 2^{\frac{802}{27}} \cdot 3^6 \cdot 3^3

2^{\frac{802}{27}} \cdot 3^9

4 0
3 years ago
I'll mark brainlliest<br>use the values in the table to the deternine slope​
NemiM [27]

Answer:

-3/2

Step-by-step explanation:

lets take coordinates:

(-4,19)  and (-2,16)

-4=x1

19=y1

-2=x2

16=y2

so

(16-19)/(-2)--4

-3/2

Hope this helps!

5 0
3 years ago
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