Question

PLZ HELP ME ON THIS PROBLEM ASAP... PLZ AND THANK YOU

Answer 1

For this case we must change the following equation:

$y = a (x-h) ^ 2 + k$ to the standard form: $y = ax ^ 2 + bx + c$

By definition we have to:

$(a-b) ^ 2 = a ^ 2-2ab + b ^ 2$

Then, rewriting:

$y = 4 (x-5) ^ 2 + 7\\y = 4 (x ^ 2-2 * 5 * x + 5 ^ 2) +7$

Applying distributive property to the terms within parentheses:

$y = 4x ^ 2-40x + 100 + 7$

Finally we have:

$y = 4x ^ 2-40x + 107$

Answer:

$y = 4x ^ 2-40x + 107$

Answer 2

Answer: y=4x^2-40x+107

Just distribute the equation.

y=4(x-5)^2+7

y=4(x^2-10x+25)+7

y=4x^2-40x+100+7

y=4x^2-40x+107