I think the answer is 7.725 so sorry if I’m wrong but see if that answer is correct
Answer:
Step 1: Set the expression inside the square root greater than or equal to zero. Step 2: Solve the equation found in step 1. In this case, we divided by a negative number, so had to reverse the direction of the inequality symbol. Step 3: Write the answer using interval notation.
Answer: The smallest valuest value for<em> k </em>is 10, such that LCM o<em>f k</em> and 6 is 60.
Step-by-step explanation:
We know that, LCM = Least common multiple.
For example : LACM of 12 and 60 is 60.
If LCM of k and 6 is 60.
i.e. the least common multiple of k and 6 is 60.
Since, 10 x 6 = 60.
The smallest valuest value for<em> k </em>should be 10, such that LCM o<em>f k</em> and 6 is 60.
Hence, the smallest value of k is 10.
Answer:
Step-by-step explanation:12 customers per hour..
4minutes per customer..
Time customers must wait= 12customers ×4minutes =48 minutes.. The clerk use 48minutes to attend to 12customers in one hour leaving him with 12spare minutes.
(B)since the clerk has 12 minute to spare it means each customer have a minute to wait before getting attention..
(C)number of customers waiting =12/2=6customers...
Answer:
Step-by-step explanation:
LOL The graph doesn’t match the y intercept :)
Anyway
If we have point (0,-3) we have a quadratic of
y=ax^2+bx-3 we are given points (-1,0) and (2,0) so
a-b-3=0 and 4a+2b-3=0
4a+2b-3+2(a-b-3)=0
4a+2b-3+2a-2b-6=0
6a-9=0
6a=9
a=1.5, since a-b=3
1.5-b=3
b=-1.5
y=1.5x^2-1.5x-3
